Answer:
1. |y| sqrt(10)
2. |x| sqrt(x)
3. a^2 sqrt(a)
4. 4 |y|^3 sqrt(3)
5. 1/4 *|x| sqrt(3x)
Step-by-step explanation:
1. sqrt(10y^2)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(y^2) sqrt(10)
|y| sqrt(10)
We take the absolute value of y because -y*-y = y^2 and the principle square root is y
2. sqrt(x^3)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(x^2) sqrt(x)
|x| sqrt(x)
3. sqrt(a^5)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(a^4) sqrt(a)
a^2 sqrt(a)
4. sqrt(16 y^7)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(16) sqrt(y^6)sqrt(y)
4 |y|^3 sqrt(3)
5. sqrt(3/16x^3)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(1/16) sqrt(x^2)sqrt(3x)
1/4 *|x| sqrt(3x)
The answer would be b
hope that helps
A hyperbola with a center at (0, 0) can be defined as x²/a² − y²/b² = ±1.<span>
</span>The statement "<span>The symmetry of a hyperbola with a center at (h, k) only occurs at y = k" </span>is false, because a hyperbola have many different orientations.
It doesn't have to be symmetric about the lines y = k or x = h.
Answer:
176 sweets
Step-by-step explanation:
162 - 30 = 132 this finds the 3/4 before he purchased more sweets.
132 divided by 3 = 44 This finds how many thirds their are. (We do 3 not 4 because 1/4 is already gone and there are only 3rds lefts.)
44 x 4 = 176 This finds the total before he purchased more.
Hope this helps!
Answer:
What is the circumference of a circle with diameter 8cm? Circumference of a circle = 3.14 x d 3.14 x 8 = 25.12 Therefore the circumference of a circle with the diameter of 8cm is 25.12cm. What is...
Step-by-step explanation: