Answer:
30 m/s
Step-by-step explanation:
Let's say the distance from the first car to the intersection is x, and the distance from the second car to the intersection is y.
The distance between the cars can be found with Pythagorean theorem:
d² = x² + y²
Taking derivative with respect to time:
2d dd/dt = 2x dx/dt + 2y dy/dt
d dd/dt = x dx/dt + y dy/dt
We know that x = 200, dx/dt = -25, y = 150, and dy/dt = -50/3.
To find dd/dt, we still need to find d.
d² = x² + y²
d² = (200)² + (150)²
d = 250
Plugging everything in:
250 dd/dt = (200) (-25) + (150) (-50/3)
dd/dt = -30
The cars are approaching each other at a rate of 30 m/s at that instant.
The answer is. D. (-6,7)
To solve the exercise you should be aware that you should primarily locate the location of park on the abscissa-x_axis ( West - East. ) followed by locating the latter on the ordinate- Y_axis (South - North). So first u start by drawing a line perpendicular ( makes a 90 degrees ) to the X_axis to find that it cuts it in a point of coordinates (-6,0) and then do the same on the Y_axis to find that it cuts it in a point of coordinates (0,7). Thus you conclude that the park is found on (-6,7) count 6 boxes to the left-west and then 7 upwards- north.
Answer:
value of x is 20
Step-by-step explanation:
If u got any doubt regarding this u can ask anytime :)
Answer:
19
Step-by-step explanation:
Answer:
measure of angle UMN is 160.
hope u got it...
