Answer:
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C) change to water at the same temperature
Explanation:
Adding 334Joules of heat to one gram of ice at STP will cause ice to change to water at the same temperature.
- The heat of fusion is the amount of energy needed to melt a given mass of a solid
- It is also conversely the amount of energy removed from a substance to freeze it.
- The addition of this energy does not cause a decrease or increase in temperature.
- Only a phase change occurs.
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The second illustration is the best representation of the change in the movement of particles as the temperature of the water changes.
<u>Explanation:</u>
The second option perfectly represents the boiling of water. As when the temperature is increased, the water molecules gain energy to move faster, thus their kinetic energy of the atoms will be more. This will lead to more freely movement of all the atoms of the water.
And as boiling leads to transformation from liquid state to gaseous state, so the increase in the distance between atoms and molecules occurs in the gaseous state. Thus, the second illustration is best suitable for representing the boiling of water.
As on increasing temperature of the water, the distance between the molecules is increasing in the second illustration while the other illustration shows the decrease in the distance between the molecules. So, the second illustration is the best representation of the change in the movement of particles as the temperature of the water changes.
Answer:
-10778.95 J heat must be removed in order to form the ice at 15 °C.
Explanation:
Given data:
mass of steam = 25 g
Initial temperature = 118 °C
Final temperature = 15 °C
Heat released = ?
Solution:
Formula:
q = m . c . ΔT
we know that specific heat of water is 4.186 J/g.°C
ΔT = final temperature - initial temperature
ΔT = 15 °C - 118 °C
ΔT = -103 °C
now we will put the values in formula
q = m . c . ΔT
q = 25 g × 4.186 J/g.°C × -103 °C
q = -10778.95 J
so, -10778.95 J heat must be removed in order to form the ice at 15 °C.
