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Lelu [443]
3 years ago
11

Consider the following equilibrium system: 3O2(g)  2O3(g); Keq = 1 Which equation compares the concentration of oxygen and ozone

?
A. [O2]3 = [O3]2

B. [O2] = [O3]

C. [O2] = [O3]3/2

D. [O2]2 = [O3]3
Chemistry
2 answers:
Rashid [163]3 years ago
7 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

 <span>3O2(g) <--> 2O3(g); 

Keq = 1 = [O3]^2/[O2]^3 

So [O2]^3 = [O3]^2 

Thus A) is correct</span>
otez555 [7]3 years ago
5 0

Answer: [O_2]^3=[O_3]^2

Explanation: Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

For the given reaction:

3O_2(g)\rightleftharpoons 2O_3(g)

K_{eq}=\frac{[O_3]^2}{[O_2]^3}

Given :K_{eq}=1

Thus 1=\frac{[O_3]^2}{[O_2]^3}

[O_2]^3=[O_3]^2

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