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Natasha2012 [34]
2 years ago
9

8. How much heat, in kilojoules, is needed to produce 1850 grams of ammonia (NH3),

Chemistry
1 answer:
AleksAgata [21]2 years ago
6 0

Based on the enthalpy of the reaction, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).

<h3>What is heat of reaction?</h3>

The heat of reaction or enthalpy change is the heat absorbed or evolved when reactant molecules react to form products.

According the enthalpy value of the reaction, 4 moles of ammonia require 1530 kJ of heat for its formation.

Molar mass of ammonia = 17 g

Mass of 4 moles of ammonia = 4 × 17 = 68 g

1850 g of ammonia will require = 1850 × 1530/68 = 41625 kJ of heat.

Therefore, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).

Learn more about enthalpy at: brainly.com/question/14047927

#SPJ1

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A reaction that is second-order in one reactant has a rate constant of 1 × 10–2 L/mol · s. If the initial concentration of the r
Harlamova29_29 [7]

Answer : It take time for the concentration to become 0.180 mol/L will be, 277.8 s

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 1\times 10^{-2}mol/L.s

t = time taken  = ?

[A] = concentration of substance after time 't' = 0.180 mol/L

[A]_o = Initial concentration = 0.360 mol/L

Putting values in above equation, we get:

1\times 10^{-2}=\frac{1}{t}\left (\frac{1}{0.180}-\frac{1}{0.360}\right)

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Answer:

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Step 1: Given and required data

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Step 2: Calculate the moles (n) of ammonia (solute)

Molarity is equal to the moles of solute divided by the liters of solution.

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