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sineoko [7]
3 years ago
13

Justin and George bought some baked goods. Justin purchased 5 cookies for x dollars each and 4 doughnuts for y dollars each and

spent $12 dollars on the baked goods. George purchased 1 cookie for x dollars each and 6 doughnuts for y dollars each and spent $5. The system of equations represents this situation. What statement is true? 5x+4y=12 x+6y=5
Mathematics
2 answers:
borishaifa [10]3 years ago
8 0

The given statement 5x=4y=12 and x+6y=5 is true.

<u>Step-by-step explanation:</u>

The question comes from linear equations in two variables.

Here, two unknown variables represent a certain situation and their value can be obtained by solving both the given equations.

The cost of cookie is represented by the variable x and cost of doughnuts can be represented by the variable y.

The coefficient of each variable in the equation represent the quantity or the number of units of each baked good.

On comparing the given equations from the data provided in the question, the statement can be stated as true.

Phoenix [80]3 years ago
8 0

Answer:

A cookie cost $1.50 more than a doughnut

Step-by-step explanation:

Hey, I believe you forgot the statements, but if they're the same as the ones I had on my test, the correct statement should be "A cookie cost $1.50 more than a doughnut". :)

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The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
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As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

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Step-by-step explanation:

I belive the answer would be 18.30$, because if 1 hat is 6.70$ you mutiply it by 13 and which is 87.10$ -  325$ overall and the which is 237.9 then diveied that by 13 and get 18.30$ for each ball?

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0.9 is the answer hope it helps.
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