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ikadub [295]
2 years ago
12

In a game, a player earns 100 points for each question answered correctly and earns -30 points for each question answered incorr

ectly. A player answers 14 questions correctly and 6 questions incorrectly. Write a numeric expression to represent the total number of points the player earmed.
Mathematics
1 answer:
Zanzabum2 years ago
7 0

Answer:

14(100) - 6(30)

Step-by-step explanation:

If the person earns 100 points for each question answered correctly and they got 14 correct, then you would simply multiply 100 by 14, getting 1400. Then, if they lose 30 points for each question answered incorrectly and they got 6 incorrect, you would do the same thing, getting 180.

If you need to solve this expression, the answer would be 1220. An amazing SAT score! xD (this is only a game, but still a good score)

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There are 7 acts in a talent show.
lara31 [8.8K]

Answer:

<u><em></em></u>

  • <u><em>Event A: 1/35</em></u>
  • <u><em>Event B: 1/840</em></u>

<u><em></em></u>

Explanation:

<u>Event A</u>

For the event A, the order of the first 4 acts does not matter.

The number of different four acts taken from a set of seven acts, when the order does not matter, is calculated using the concept of combinations.

Thus, the number of ways that the first <em>four acts</em> can be scheduled is:

          C(m,n)=\dfrac{m!}{n!(m-n)!}

         C(7,4)=\dfrac{7!}{4!(7-4)!}=\dfrac{7!}{4!(3)!}=35

And<em> the number of ways that four acts is the singer, the juggler, the guitarist, and the violinist, in any order</em>, is 1: C(4,4).

Therefore the<em> probability of Event A</em> is:

           P(A)=1/35

Event B

Now the order matters. The difference between combinations and permutations is ordering. When the order matters you need to use permutations.

The number of ways in which <em>four acts </em>can be scheculed when the order matters is:

           P(m,n)=\dfrac{m!}{(m-n)!}

         P(m,n)=\dfrac{7!}{(7-4)!}=P(m,n)=\dfrac{7!}{4!}=840

The number of ways <em>the comedian is first, the guitarist is second, the dancer is third, and the juggler is fourth</em> is 1: P(4,4)

Therefore, <em>the probability of Event B</em> is:

            P(B)=1/840

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