<span>Answer:
Ground state of Hydrogen = -13.6 eV Energy of photon emission: E = hf = hc/λ = 6.6256E-34 (3E8)/680E-9 E = 0.0292E-17 J(1 eV/1.6E-19 J) = 1.825 eV E(photon) = 1.825 eV Bandgap energy: ΔE = E – Eo = 1.825 – (-13.6) = 15.425 eV</span>
Answer:
In the absence of urease this will take 950 * 10^6 years to completely hydrolyze
Explanation:
The enzyme urease enhances the rate of urea hydrolysis at pH 8.0 and 20 degrees by a factor of 10^14 . If a given quantity of urease can completely hydrolyze a given quantity of urea in 5 min at 20 degrees and pH 8.0, how long would it take for this amount of urea to be hydrolyzed under the same conditions in the absence of urease?
Step 1: data given
The enzyme urease enhaces the rate of urea hydrolysis at pH = 8.0 of centigrade by a factor of 10^14
Temperature = 20.0 °C
Step 2: Calculate the time it takes to completely hydrolyze without urease
This means when urease is available it takes 5 minutes to completely hydrolyze
When urease is not available it will take 5 *10^14 minutes
5 * 10^14 min = 5 * 10^14 minutes
Since 1 hour = 60 minutes
1 day = 24 hours = 24 *60 minutes = 1440 minutes
It would take : 5 * 10^14 minutes / 1440 minutes = 347222222222.2 days
Since 1 year = 365 days
This will take: 347222222222.2 / 365.25 = 950642634.4 years
This 950 * 10^6 years
In the absence of urease this will take 950 * 10^6 years
Answer: It will produce 40 chloride ions
Explanation: When in water, Calcium chloride separate in ions, as the following chemical equation:
CaCl₂ + H₂O ⇒
According to the equation, 1 calcium chloride results in 2 chloride ions, so if there are 20 units of the chemical compound, there will be 2 times as much Chlorine ions, i.e., 40 units of chlorine ions.
The answer is a. The positive and negative ions balance each other out.