<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>BUNSEN BURNER:</h2>
Bunsen burner is an instrument which is used as a source of heat using natural gas or petrol. It is used for the heating, sterlization, and combustion. Bunsen burner is named after its inventor Robert bunsen.
<h2>____________________________________</h2><h3>Mechanism:</h3>
Burner provide a single, continuous flame by mixing gas with air in a controlled fashion. The ratio of gas to air that is mixed together can be manually adjusted, allowing the user to control the intensity, temperature, and size of the flame.
<h2>____________________________________</h2><h3>PICTURE IS ATTACHED BELOW</h3><h2>____________________________________</h2><h2>Best Regards!</h2><h2>'Borz'</h2>
Answer:
∴ The absolute pressure of the air in the balloon in kPa = 102.69 kPa.
Explanation:
- We can solve this problem using the general gas law:
<em>PV = nRT</em>, where,
P is the pressure of the gas <em>(atm)</em>,
V is the volume of the gas in L <em>(V of air = 6.23 L)</em>,
n is the no. of moles of gas <em>(n of air = 0.25 mole)</em>,
R is the general gas constant <em>(R = 0.082 L.atm/mol.K)</em>,
T is the temperature of gas in K <em>(T = 35 °C + 273 = 308 K</em>).
∴ P = nRT / V = (0.25 mole)(0.082 L.atm/mol.K)(308 K) / (6.23 L) = 1.0135 atm.
- <em>Now, we should convert the pressure from (atm) to (kPa).</em>
1.0 atm → 101.325 kPa,
1.0135 atm → ??? kPa.
∴ The absolute pressure of the air in the balloon in kPa = (101.325 kPa)(1.0135 atm) / (1.0 atm) = 102.69 kPa.
The grams of hydrogen gas can be burned if 40. liters of oxygen at 200. k and 1.0 atm is 4.88 grams.
<h3>How do we calculate grams from moles?</h3>
Grams (W) of any substance will be calculated by using their moles (n) through the following equation:
M = molar mass
And moles of the gas will be calculated by using the ideal gas equation as:
P = pressure = 1atm
V = volume = 40L
n = moles = ?
R = universal gas constant = 0.082 L.atm / K.mol
T = temperature = 200K
On putting these values on the above equation, we get
n = (1)(40) / (0.082)(200) = 2.439 = 2.44 moles
- Now grams of hydrogen gas will be calculated by using the first equation as:
W = (2.44mol)(2g/mol) = 4.88g
Hence required mass of hydrogen gas is 4.88g.
To know more about ideal gas equation, visit the below link:
brainly.com/question/15046679
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<span>(1) For multiplication and division, you determine the number of significant digits in each number in your problem. The significant digits of your answer is determined by the number with fewer digits. (2) For addition and subtraction, you determine the place value of each number in your problem. The significant digits of the answer is determined by the number that is least precise.</span>
Water is a bent molecule, so it is polar.
