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ANEK [815]
3 years ago
12

What is the number of molecules present in 1.12 dm^3 of nitrogen gas at STP​

Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

Answer:

\huge\boxed{\sf No.\ of\ molecules = 3 * 10\²\² \ molecules}

Explanation:

<u>Given Data:</u>

Volume = v = 1.12 dm³ = 1.12 L

Density of nitrogen at STP = D = 1.25 g / L

Molar mass = M = 14 * 2 = 28 g / mol

Avogadro's Number = \tt{N_{A}} = 6.023 * 10²³ mol⁻¹

<u>Required:</u>

No. of molecules = ?

<u>Formula:</u>

\tt{No. \ of \ molecules = \frac{Density * Volume}{Molar\ Mass} * N_{A}}

<u>Solution:</u>

No. of molecules = (1.25*1.12) / 28 * (6.023 * 10²³)

No. of molecules = ( 1.4 / 28 ) * 6.023 * 10²³

No. of molecules = 0.05 * 6.023 * 10²³

No. of molecules = 0.3 * 10²³

No. of molecules = 3 * 10²² molecules

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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