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2 years ago

3n - 5p + 2n = 10p, solve for n

1 answer:

4 0

Combine (subtract) 3n and 2n to get 1n or n. Then you have n -5n =10n add 5n to 10n to get 15n. divide the 15 from n and your answer is n=15

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John Gray bought a Bessie call for $32,750 with options that cost $375 there's a 6% sales tax in his state and a combined 50 lig

NikAS [45]

What? You bought a call with options, and 50 lightning??

5 0

3 years ago

after selling tickets to a dance for $3.25 each, the student council brought in $1020.50from tocket sales. how many tickets did

balu736 [363]

3.25x = 1020.50

/3.25 /3.25

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7 0

3 years ago

The angle by which AB turns clockwise about point B to coincide with BC is ? degrees. If from point B, a point E is drawn direct

dedylja [7]

Answer:

Step-by-step explanation:

We have the statement AB turns clockwise to coincide with BC.

= ABD + DBC

= 33.3° + 30.6°

= 63.9°

Now we have the statement a point E is drawn directly opposite point C. B, E, and C are on the same straight line

EBC is a straight line, so sum of angles =180°

ABE + ABD + DBC = 180°

ABE + 33.3° + 30.6° = 180°

ABE + 63.9° = 180°

ABE = 180 - 63.1

ABE = 116.9° ....

3 0

3 years ago

Indira is using a number line to add –1 + (–3). She begins by showing –1 on the number line, as shown below. What is the sum of

Naddik [55]

The answer is -4, because -1+-3=-4

5 0

3 years ago

Read 2 more answers

A Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer; a sample

8090 [49]

Answer:

Step-by-step explanation:

Step(i):-

Given first random sample size n₁ = 500

Given Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer.

First sample proportion

$p^{-} _{1} = \frac{65}{500} = 0.13$

Given second sample size n₂ = 700

Given a sample of 700 men (unrelated to the women) ages 18-29 found that 133 men said that they had the most say when purchasing a computer.

second sample proportion

$p^{-} _{2} = \frac{133}{700} = 0.19$

Level of significance = α = 0.05

critical value = 1.96

Step(ii):-

Null hypothesis : H₀: There is no significance difference between these proportions

Alternative Hypothesis :H₁: There is significance difference between these proportions

Test statistic

$Z = \frac{p_{1} ^{-}-p^{-} _{2} }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }$

where

$P = \frac{n_{1} p^{-} _{1}+n_{2} p^{-} _{2} }{n_{1}+ n_{2} } = \frac{500 X 0.13+700 X0.19 }{500 + 700 } = 0.165$

Q = 1 - P = 1 - 0.165 = 0.835

$Z = \frac{0.13-0.19 }{\sqrt{0.165 X0.835(\frac{1}{500 } +\frac{1}{700 } )} }$

Z = -2.76

|Z| = |-2.76| = 2.76 > 1.96 at 0.05 level of significance

Null hypothesis is rejected at 0.05 level of significance

Alternative hypothesis is accepted at 0.05 level of significance

Conclusion:-

There is there is a difference between these proportions at α = 0.05

3 0

3 years ago