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Rus_ich [418]
3 years ago
9

Ground squirrels inhabit African savannas. Which adaptation helps the ground squirrels live in this biome? tan coloring to blend

in with the surroundings thick fur to conserve heat sharp claws for climbing trees white coloring to blend in with the surroundings
Biology
2 answers:
Rasek [7]3 years ago
5 0

Answer:

sharp claws for climbing trees

Explanation:

lana [24]3 years ago
3 0

The correct answer is sharp claws for climbing trees.  

Animal adaptations are behavioral and physical adaptations, which assists animals to thrive and survive in their local habitats. When animals thrive in a habitat for a specific time, they ultimately establish mannerisms and physical characteristics, which assist them to work better in that surrounding.  

The ground squirrels in African savannas live in underground burrows that they dig with the help of their sharp claws. The ground squirrels utilize their claws to form a better grip as they climb trees to reach and collect seeds. The claws also function as a defense mechanism to safeguard themselves and their young when they are attacked or threatened.  


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Beyond their role in energy transfer, what other benefit do microorganisms that act as producers provide for ecosystems?
insens350 [35]

Answer:

The microorganisms present metabolic wastes that serve as the primary source of food for other living things.

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This property is restricted only to prokaryotes and is widely distributed among different groups of bacteria and some archaeobacteria. It is a process that consumes a lot of energy that occurs with the mediation of the enzyme nitrogenase, which the rest of the living organisms that cannot do or comply with this process is because they lack said enzyme.

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Explanation:

By nitrogen fixation is meant the combination of molecular nitrogen or dinitrogen with oxygen or hydrogen to give oxides or ammonia that can be incorporated into the biosphere. Molecular nitrogen, which is the majority component of the atmosphere, is inert and not directly usable by most living things. Nitrogen fixation can occur abiotic (without the intervention of living beings) or by the action of microorganisms (biological nitrogen fixation). Fixation in general involves the incorporation into the biosphere of a significant amount of nitrogen, which globally can reach about 250 million tons per year, of which 150 correspond to biological fixation.

6 0
3 years ago
For each of the following statements, indicate
stepan [7]

The plants that were allowed to self pollinate were the F1 plants.

The plants that are true breeding are P generation plants.

The plants where there were 3times as many tall plants as short plants are in F2 generation.

<h3><u>Explanation:</u></h3>

This question is based on the Mendel’s Experiment. Sir Gregor Johann Mendel was the father of genetics who experimented on garden pea plants <em>Pisum</em> <em>sativum</em> to see whether the characters got mixed or not and to know the real cause behind different traits of same character in plants.

He took the pure homozygous tall and short plants separately which he called as parental generation or P generation. These plants were homozygous, hence pure breeding.

As these plants were crossed between themselves, then the F1 generation showed all tall plants. This is because of the heterozygous plants which showed character of dominant trait. These plants were allowed to self pollinate.

As a result of self pollination of the F1 plants, the F2 plants were 75% tall in number whereas the other 25% short, which gave the phenotypic ratio of 3:1.

4 0
3 years ago
Read 2 more answers
What is the difference between continuous and discontinuous variation?
ira [324]
Discontinuous variation <span> refer to large, conspicuous differences from the parents</span>
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continious variation refer to small, indistinct differences from the normal condition.
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6 0
3 years ago
The area of biology devoted to the study of fungi is known as?
MakcuM [25]
<span>Answer: mycologist []</span>
8 0
3 years ago
Each child born to a particular set of parents has probability 0.25 of having blood type o. if these parents have 5 children, wh
Taya2010 [7]
Use binomial distribution with p=0.25, n=5, x=2
P(X=x)=C(n,x)p^x (1-p)^(n-x)

P(X=2)=C(5,2) 0.25^2 0.75^(5-2)
=10*0.0625*0.421875
=0.26367

So the probability of 2 of 5 children having type-O blood from these parents is 0.26367.

7 0
3 years ago
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