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Elina [12.6K]
3 years ago
8

A 10-mm-diameter Brinell hardness indenter produced an indentation 1.55 mm in diameter in a steel alloy when a load of 500 kg wa

s used. Calculate the Brinell hardness (in HB) of this material.
Engineering
1 answer:
artcher [175]3 years ago
4 0

Answer:

HB=131.69      

Explanation:

Given that

Diameter ,    D= 10 mm

Depth of indentation ,d= 1.55 mm

Load ,P =500 kg

Brinell hardness is given as

HB=\dfrac{P}{\pi D(D-\sqrt{D^2-d^2})}

Now by putting the values in the above equation we get

HB=\dfrac{500}{\pi \times 10\times (10-\sqrt{10^2-1.55^2})}

HB=131.69

Therefore the hardness of the material will be 131.69 HB.

   

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In a year, roughly (to 20% accuracy) how much energy does the U.S. obtain from wind? (a) 25 quads (b) 250 quads (c) 2.5 quads (d
garik1379 [7]

Answer:

c

Explanation:

A data graph has been attached to the given question which is of the year 2018.

According to it of 101.3 quad Btu total energy produced in USA, 11% is produced by renewable energy resources. that consists of 22% of from wind energy.

there amount of energy produced through wind is 22% of 11% of 101.3 quad Btu, which will be roughly about 2.5 quad Btu

Btu here is British thermal Unit.

hence option c is correct  

3 0
4 years ago
Match the following light concepts
Gelneren [198K]

Answer:

- Light is bounced back at same angle    (Classical Reflection)

- Light penetrates medium at different angle due to different material densities     (Refraction)

Light bounces at different angles in periodic grid     (Reflected Diffraction)

Light enters medium at different angles through a grid     (Transmission Diffraction)

- Light EMF field looses one axis component     (Polarized filter)

Explanation:

Reflection is a phenomenon in which waves (light included) bounce back from an obstacle at the same angle of incidence

Refraction is the change in the angle of a wave as it enters the interface of two media. The change in angle is due to the difference in the densities of the two media.

Reflected diffraction occurs when an optical component with a periodic grid, splits, and diffracts light into several beams travelling in different directions. The light light bounces at an angle in the periodic grid.

Transmission diffraction is dispersion a beam of various wavelengths into a spectrum of associated lines due to the principle of diffraction. In this type of diffraction, light enters medium at different angles through a grid.

Polarized filters removes one field from the incidence electromagnetic wave like light, leaving it to vibrate in only one plane.

6 0
4 years ago
How could increasing the budget for testing have prevented the problem experienced by the mars orbiter?
vlada-n [284]

Answer:

this might help

Explanation:

https://science.ksc.nasa.gov/mars/msp98/misc/MCO_MIB_Report.pdf

5 0
3 years ago
Assume we have already defined a variable of type String called password with the following line of code: password' can have any
omeli [17]

Answer:

The Java code is given below with appropriate comments for better understanding

Explanation:

import java.util.Scanner;

public class ValidatePassword {

  public static void main(String[] args) {

      Scanner input = new Scanner(System.in);

          System.out.print("Enter a password: ");

          String password = input.nextLine();

          int count = chkPswd(password);

          if (count >= 3)

              System.out.println("Secure");

          else

              System.out.println("Not Secure");

  }

  public static int chkPswd(String pwd) {

      int count = 0;

      if (checkForSpecial(pwd))

          count++;

      if (checkForUpperCasae(pwd))

          count++;

      if (checkForLowerCasae(pwd))

          count++;

      if (checkForDigit(pwd))

          count++;

      return count;

  }

  // checks if password has 8 characters

  public static boolean checkCharCount(String pwd) {

      return pwd.length() >= 7;

  }

  // checks if password has checkForUpperCasae

  public static boolean checkForUpperCasae(String pwd) {

      for (int i = 0; i < pwd.length(); i++)

          if (Character.isLetter(pwd.charAt(i)) && Character.isUpperCase(pwd.charAt(i)))

              return true;

      return false;

  }

  public static boolean checkForLowerCasae(String pwd) {

      for (int i = 0; i < pwd.length(); i++)

          if (Character.isLetter(pwd.charAt(i)) && Character.isLowerCase(pwd.charAt(i)))

              return true;

      return false;

  }

  // checks if password contains digit

  public static boolean checkForDigit(String pwd) {

      for (int i = 0; i < pwd.length(); i++)

          if (Character.isDigit(pwd.charAt(i)))

              return true;

      return false;

  }

  // checks if password has special char

  public static boolean checkForSpecial(String pwd) {

      String spl = "[email protected]#$%^&*(";

      for (int i = 0; i < pwd.length(); i++)

          if (spl.contains(pwd.charAt(i) + ""))

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      return false;

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