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3 years ago

What are the functions of the peripheral nervous system

Engineering

2 answers:

Margaret [11]3 years ago

5 0

Answer:

The peripheral system allows the brain and spinal cord to receive and send information to other areas of the body, which allows us to react to stimuli in our environment.

The nerves that make up the peripheral nervous system are actually the axons or bundles of axons from nerve cells or neurons.

Reptile [31]3 years ago

4 0

The peripheral nervous system
The PNS functions via a series of reflex arc circuits with afferent and efferent arms controlled by the CNS. An understanding of the many PNS disorders requires an understanding of the complexities of the macro- and microanatomy of peripheral nerves, as well as their molecular biology, immunology, and pathophysiology

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The smallest crystal lattice defects is a) cracks b) point defects c) planar defects d) dislocations.

ss7ja [257]

Answer:b) Point defects

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Wewaii [24]

Answer:

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3 years ago

The voltage across a device and the current through it are:

butalik [34]

Answer:

attached below

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3 years ago

Read 2 more answers

The section should span between 10.9 and 13.4 cm (4.30 and 5.30 inches) as measured from the end supports and should be able to

Sergeeva-Olga [200]

Answer:

hello below is missing piece of the complete question

minimum size = 0.3 cm

answer : 0.247 N/mm2

Explanation:

Given data :

section span : 10.9 and 13.4 cm

minimum load applied evenly to the top of span : 13 N

maximum load for each member ; 4.5 N

lets take each member to be 4.2 cm

Determine the max value of P before truss fails

Taking average value of section span ≈ 12 cm

Given minimum load distributed evenly on top of section span = 13 N

we will calculate the value of by applying this formula

= $\frac{Wl^2}{12} = (0.013 * 0.0144 )/ 12$ = 1.56 * 10^-5

next we will consider section ; 4.2 cm * 0.3 cm

hence Z (section modulus ) = BD^2 / 6

= ( 0.042 * 0.003^2 ) / 6 = 6.3*10^-8

Finally the max value of P( stress ) before the truss fails

= M/Z = ( 1.56 * 10^-5 ) / ( 6.3*10^-8 )

= 0.247 N/mm2

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3 years ago