on the same scale for stress, the tensile true stress-true strain curve is higher than the engineeringstress-engineering strain
1 answer:
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Answer:
Explanation:
m = Mass of water = 749511.5 kg
c = Specific heat of water = 4182 J/kg ⋅°C
= Change in temperature =
Cost of 1 GJ of energy = $2.844
Heat required is given by
Amount of heat required to heat the water is .
Cost of heating the water is
Cost of heating the water to the required temperature is .
Answer:
Explanation:
The vessel is modelled after the First Law of Thermodynamics. Let suppose the inexistence of mass interaction at boundary between vessel and surroundings, changes in potential and kinectic energy are negligible and vessel is a rigid recipient.
Properties of water at initial and final state are:
State 1 - (Liquid-Vapor Mixture)
State 2 - (Liquid-Vapor Mixture)
The mass stored in the vessel is:
The heat transfer require to the process is:
Answer:
For any string, we use
Explanation:
The pumping lemma says that for any string s in the language, with length greater than the pumping length p, we can write s = xyz with |xy| ≤ p, such that xyi z is also in the language for every i ≥ 0. For the given language, we can take p = 2.
Here are the cases:
- Consider any string a i b j c k in the language. If i = 1 or i > 2, we take
and y = a. If i = 1, we must have j = k and adding any number of a’s still preserves the membership in the language. For i > 2, all strings obtained by pumping y as defined above, have two or more a’s and hence are always in the language.
- For i = 2, we can take and y = aa. Since the strings obtained by pumping in this case always have an even number of a’s, they are all in the language.
- Finally, for the case i = 0, we take