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marysya [2.9K]
3 years ago
6

Find the inequality represented by the graph

Mathematics
1 answer:
Naily [24]3 years ago
3 0

Answer:

There is no graph to find an inequality on...

Step-by-step explanation:

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How many degrees has ABC been rotated counterclockwise about the<br> origin?
omeli [17]

Answer:

C

Step-by-step explanation:

It would take 90 degree to rotate clockwise so it will take 360-90=270 degree to rotate counterclockwise

3 0
3 years ago
Read 2 more answers
Find all geometric sequences such that the sum of the first two terms is 24 and the sum of the first three terms is 26.
Serga [27]

Answer:

<h3>The nth term Tn = -8(-1/4)^(n-1) or Tn = 6(1/3)^(n-1) can be used to find all geometric sequences</h3>

Step-by-step explanation:

Let the first three terms be a/r, a, ar... where a is the first term and r is the common ratio of the geometric sequence.

If the sum of the first two term is 24, then a/r + a = 24...(1)

and the sum of the first three terms is 26.. then a/r+a+ar = 26...(2)

Substtituting equation 1 into 2 we have;

24+ar = 26

ar = 2

a = 2/r ...(3)

Substituting a = 2/r into equation 1 will give;

(2/r))/r+2/r = 24

2/r²+2/r = 24

(2+2r)/r² = 24

2+2r = 24r²

1+r = 12r²

12r²-r-1 = 0

12r²-4r+3r -1 = 0

4r(3r-1)+1(3r-1) = 0

(4r+1)(3r-1) = 0

r = -1/4 0r 1/3

Since a= 2/r then a = 2/(-1/4)or  a = 2/(1/3)

a = -8 or 6

All the geometric sequence can be found by simply knowing the formula for heir nth term. nth term of  a geometric sequence is expressed as

if r = -1/4 and a = -8

Tn = -8(-1/4)^(n-1)

if r = 1/3 and a = 6

Tn = 6(1/3)^(n-1)

The nth term of the sequence above can be used to find all the geometric sequence where n is the number of terms

6 0
3 years ago
How do you solve this problem?
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3 0
3 years ago
1. A weighted coin is biased so that a head is twice as likely to occur as a tail. If the coin is tossed 4 times, what is the pr
ohaa [14]

Answer:

80/81

Step-by-step explanation:

If a head is twice as likely to occur as a tail, then the probability of getting heads is 2/3 and the probability of getting tails is 1/3.

The probability of getting at least 1 head involves 4 scenarios:

1) 1 Head and 3 Tails

2) 2 Heads and 2 Tails

3) 3 Heads and 1 Tail

4) 4 Heads

Instead of calculate all these scenarios, you could calculate the opposite scenario: 4 Tails. The sum of all possible scenarios is 1, so:

P(at least one head) + P(no heads) = 1

Then, P(at least one head) = 1 - P(no heads)

The probability of 4 tails is:

P(no heads) = P(TTTT) = (1/3)(1/3)(1/3)(1/3)=1/81

Then, P(at least one head) = 1 - 1/81=80/81

7 0
3 years ago
Find a26 of the sequence-2,-8,-14,-20
ddd [48]

The numbers decrease by 6.

-1, -8, -14, -20, -26, -32, -38, -44, -50, -56, -62, -68, -74, -80, -86, -92, -98, -104, -110, -116, -122, -128, -134, -140, -146

4 0
3 years ago
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