Answer:
π = 4,882 atm
Explanation:
To calculate the osmotic pressure (π), the <em>Van´t Hoff equation</em> must be used, which is:
π x V = n x R x T
<em>Where:
</em>
• π: Osmotic pressure, which is the difference between the levels of the solution and the pure solvent through a semipermeable membrane, which allows the passage of the solvent but not the solute
• V: Volume of the solution, in liters unit
• n: Number of moles of solute
• R: Constant of ideal gases, equal to 0.08206 L.atm / mol.K
• T: Absolute temperature, in Kelvin degrees
With the data you provide you can calculate the osmotic pressure by clearing it from the equation, we would be equal to:
π = (n x R x T) / V
However, all data must first be converted to the corresponding units in order to replace the values in the equation.
<em>Solution volume ⇒ go from mL to L:
</em>
1000 mL of solution ____ 1 L
2600 mL of solution _____ X = 2.6 L
Calculation: 2600 mL x 1 L / 1000 mL = 2.6 L
<em>Temperature ⇒ Go from ° C to K
</em>
T (K) = t (° C) + 273.15 = 30.0 ° C + 273.15 = 303.15 K
<em>Number of moles of solute ⇒</em> <em>It can be calculated since we have the mass of the enzyme and its molecular mass:
</em>
98.0 g of enzyme ____ 1 mol
50.0 g of enzyme _____ X = 0.510 moles
Calculation: 50.0 g x 1 mol / 98.0 g = 0.510 moles
Now, you can replace the values in the Van´t Hoff equation and you will get the result:
π = (n x R x T) / V
π = (0.510 mol x 0.08206 L.atm / mol.K x 303.15 K) / 2.6 L = 4.882 atm
Therefore, <em>the osmotic pressure will be 4,882 atm</em>
