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7nadin3 [17]
2 years ago
11

H2(g) + Co(g) _CH3OH balance the equation ​

Chemistry
1 answer:
Tom [10]2 years ago
8 0

Answer:

CO + 2H2 = CH3OH

Explanation:

1. Label Each Compound With a Variable

  aCO + bH2 = cCH3OH

2. Create a System of Equations, One Per Element

  C: 1a + 0b = 1c

  O: 1a + 0b = 1c

  H: 0a + 2b = 4c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

  a = 1

  b = 2

  c = 1

4. Substitute Coefficients and Verify Result

  CO + 2H2 = CH3OH

      L R

  C: 1 1 ✔️

  O: 1 1 ✔️

  H: 4 4 ✔️

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7 0
3 years ago
What happens when The vapour obtained by dropping conc. H2SO4 in a mixture of KI and MnO2 is treated with hypo solution​
Shalnov [3]

Iodine is decolorized.

The first reaction stated in the question occurs as follows;

2 KI (aq) + 2 H2SO4 (aq) + MnO2 (s) → MnSO4 (aq) + K2SO4 (aq) + I2 (s) + 2 H2O (l)

The reaction here is the formation of iodine from MnO2 and KI in the presence of dropwise H2SO4.

Hypo is the common name of sodium thio-sulphate or sodium hypo-sulfite.

The equation of the titration reaction is;

2Na2S2O3 + I2→ Na2S4O6 + 2NaI

When this reaction takes place, iodine is decolorized due to its reduction to I^-.

6 0
3 years ago
What is the<br> total charge of 1 proton, 1 electron, and 1 neutron?
iragen [17]

Given parameters:

Number of protons  = 1

Number of electrons = 1

Number of neutrons  = 1

unknown:

Total charge = ?

Atoms are made up of elementary particles of protons neutrons and electrons.

Protons are the positively charged particles in an atom

Electrons are the negatively charged particles

Neutrons do not carry any charges

To find the total charge on an atom; simply find the difference between the number of protons and electrons.

       Total charge  = Number of protons - number of electrons

                               = 1 - 1

       Total charge is 0

Therefore, the total charge is zero, 0

7 0
3 years ago
Which is an example of convection?
mixas84 [53]

Answer:

it is C

Explanation:

4 0
3 years ago
what is the pH of a solution that results when 0.010mol HNO3 is added to 500.ml of a solution that is 0.10M in aqueous ammonia a
WARRIOR [948]

Answer : The  

pH of a solution is, 8.56

Explanation : Given,

K_b=1.8\times 10^{-5}

Concentration of ammonia (base) = 0.10 M

Concentration of ammonium nitrate (salt) = 0.55 M

First we have to calculate the value of pK_b.

The expression used for the calculation of pK_b is,

pK_b=-\log (K_b)

Now put the value of K_b in this expression, we get:

pK_b=-\log (1.8\times 10^{-5})

pK_b=5-\log (1.8)

pK_b=4.7

Now we have to calculate the pOH of buffer.

Using Henderson Hesselbach equation :

pOH=pK_b+\log \frac{[Salt]}{[Base]}

Now put all the given values in this expression, we get:

pOH=4.7+\log (\frac{0.55}{0.10})

pOH=5.44

The pOH of buffer is 5.44

Now we have to calculate the pH of a solution.

pH+pOH=14\\\\pH+5.44=14\\\\pH=14-5.44\\\\pH=8.56

Thus, the pH of a solution is, 8.56

8 0
3 years ago
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