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Tamiku [17]
1 year ago
15

A children's liquid medicine contains 100 mg of the active ingredient in 5 mL. If a child should receive 150 mg of the active in

gredient, how many milliliters of the medicine should the child be given? For the purposes of this question, assume that these numbers are exact. The package states that one teaspoon (tsp) is approximately equal to 5 mL. Calculate the number of teaspoons that the child should receive. Use the given approximation as your conversion factor.
Chemistry
1 answer:
likoan [24]1 year ago
4 0

Answer:

Explanation: A children's liquid medicine contains 100 mg of the active ingredient in 5 mL . If a child should receive 150 mg of the active ingredient, how many milliliters

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mr oxygen= 16. 16 x 3= 48
mr Al2O3= 27 + 27 + 48= 102

(48/102) X 100%= 47.05% oxygen
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What happens to electrons in ionic bonds?
vlabodo [156]

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Hope this helps :)

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element m is a metal and its chloride has the formula mcl2. to which group of the periodic table does m most likely belong
Triss [41]
It will belong to the metals because metals bond with nonmetals like chlorine to form ionic compounds
3 0
3 years ago
Read 2 more answers
Exercise 2:
vagabundo [1.1K]

Answer:

1. KCLO3------>KCL + 3/2O2(g)

2. 122.5g/mol

3. 0.2mol

4. 18.5g

7 0
3 years ago
What mass of carbon dioxide is produced from the complete combustion of 5.30x10-3 g of methane?
pshichka [43]

Answer:

1.45 x 10⁻² g CO₂

Explanation:

To find the mass of carbon dioxide, you need to (1) convert grams CH₄ to moles CH₄ (via molar mass), then (2) convert moles CH₄ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). The final answer should have 3 sig figs to reflect the given value (5.30 x 10⁻³ g).

Molar Mass (CH₄): 12.011 g/mol + 4(1.008 g/mol)

Molar Mass (CH₄): 16.043 g/mol

Combustion of Methane:

1 CH₄ + 2 O₂ ---> 2 H₂O + 1 CO₂

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

5.30 x 10⁻³ g CH₄          1 mole              1 mole CO₂          44.007 g
---------------------------  x  ----------------  x  ---------------------  x  -----------------  =
                                      16.043 g            1 mole CH₄            1 mole

=  0.0145 g CO₂

=  1.45 x 10⁻² g CO₂

8 0
2 years ago
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