Answer:
The correct option is:
2, 4, 12, 48, 240
Step-by-step explanation:
We have to determine the first 5 terms of the sequence by using following formula:
To Calculate the first 5 terms.
Put n = 1
a₁ = 2 (1)!
a₁ = 2(1)
a₁ = 2
Put n = 2
a₂ = 2 (2)!
a₂ = 2 (2·1) = 2(2)
a₂ = 4
Put n = 3
a₃ = 2(3)!
a₃ = 2(3·2·1)
a₃ = 2(6)
a₃ = 12
Put n = 4
a₄ = 2(4)!
a₄ = 2(4·3·2·1)
a₄ = 2(24)
a₄ = 48
Put n =5
a₅ = 2(5)!
a₅ = 2(5·4·3·2·1)
a₅ = 2(120)
a₅ = 240
Hi there!
In order to solve, you can use substitution. This means that you use one equation and solve for one variable, then use that one equation and plug it into the other equation. Here's how we'd do it:
WORK:
x = 12 - y (since x is already solved for, we'll use that to plug into the other given equation.
2(12 - y) + 3y = 29 (using substitution)
24 - 2y + 3y = 29
24 + y = 29
y = 5
Plug the value of y back into the first equation
x = 12 - 5
x = 7
ANSWER:
A - x = 7, y = 5
It seems as though you're having some trouble with these questions, PLEASE MESSAGE ME!! I'd be more than happy to help you work through as many problems as you need until you get the hang of it (plus, it doesn't cost you any points!)
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Well, there isn’t really an end for numbers...
However; The biggest number referred to regularly is a googolplex (10googol), which works out as 1010^100. That isn’t the end to numbers but it is a huge one. We will replace that with ‘all the numbers in the world’.
106 is the exponent equivalent to 1 million
So your question would be:
106 x 1010^100 =
However I don’t believe there is a calculator that large.
Scientific notation is a way to write compactly numbers with lots of digits, either because they're very large (like 2393490000000000000000000), or very small (like 0.0000000000356).
We use powers of ten to describe all those leading/trailing zeros, so that we con concentrate on the significat digits alone.
In your case, the "important" part of the number is composed by the digits 6 and 1, all the other digits are zero. But how many zeroes? Well, let's do the computation.
Every power of 10, 
is written as one zero followed by n zeroes, so we have
Multiplying a number by means to shift the decimal point to the right and/or add trailing zeroes n times. So, we have to repeat this process six times. We shift the decimal point to the right one position, and then add the five remaning zeroes. The result is thus
Answer: 6.4 is the mean of the set of numbers
Step-by-step explanation:
8+4+6+6+7+7+9+4+8+5=64
64 divided by 10 = 6.4
Hope this helps!
