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3 years ago

Differentiate x^2/4-x^3

Mathematics

1 answer:

Ede4ka [16]3 years ago

8 0

Answer:

x^4 + 8x

-----------------

(4-x^3)^2

Step-by-step explanation:

d /dx (x^2/(4-x^3))

When we differentiate a fraction u/v

df/dx = u/v

= v du/dx-u dv/dx

---------------------------

v^2

we know u = x^2 so du/dx = 2x

v = (4-x^3) so dv/dx = -3x^2

d dx = (4-x^3) (2x)- x^2 ( -3x^2)

-------------------------------------

(4-x^3)^2

Combining terms

(8x-2x^4) --3x^4

-------------------------------------

(4-x^3)^2

8x-2x^4 +3x^4

-------------------------------------

(4-x^3)^2

x^4 + 8x

-------------------------------------

(4-x^3)^2

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valentina_108 [34]

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