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a_sh-v [17]
3 years ago
12

Differentiate x^2/4-x^3​

Mathematics
1 answer:
Ede4ka [16]3 years ago
8 0

Answer:

  x^4 + 8x          

  -----------------

    (4-x^3)^2

Step-by-step explanation:

d /dx  (x^2/(4-x^3)​)

When we differentiate a fraction u/v

df/dx = u/v

         =  v du/dx-u dv/dx

           ---------------------------

                         v^2

we know u = x^2   so du/dx = 2x

               v = (4-x^3)  so dv/dx = -3x^2

d dx =   (4-x^3) (2x)- x^2 ( -3x^2)

           -------------------------------------

                   (4-x^3)^2

Combining terms

           (8x-2x^4) --3x^4

           -------------------------------------

                   (4-x^3)^2

           8x-2x^4 +3x^4

           -------------------------------------

                   (4-x^3)^2

             x^4 + 8x          

           -------------------------------------

                   (4-x^3)^2

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3 years ago
Given the set of data: 24, 43, 65, 12, 31, 78, 43, 24, 25, 18, 29, 53, 18, 23, 20, 43, 53, 25 Determine the quartiles.
worty [1.4K]

Answer:

Lower quartile= 4.75

Middle quartile= 9.5

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Step-by-step explanation:

The given date set is 24, 43, 65, 12, 31, 78, 43, 24, 25, 18, 29, 53, 18, 23, 20, 43, 53, 25

On counting them we notice that it's number of element is 18

So N = 18

Arranging them in ascending order gives

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Lower quartile= (N+1)*1/4

Lower quartile= (18+1)/4

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Middle quartile= (N+1)*2/4

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4 0
3 years ago
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