Find the surface area of the cube (above) using its net (below).

Chuck built a garden in the shape of a rectangle in his backyard. The width of the garden is 7 feet and the length of the garden

Nastasia [14]

The answer is 25 because of the Pythagorean theorem. 49+576=625 625 squared=25

5 0

3 years ago

Identify the slope as positive, negative, zero or undefined

slavikrds [6]

Answer:

Zero

Step-by-step explanation:

6 0

2 years ago

45. For customers generating their own solar power, ZG&E charges them $3 per month per kilowatt (kWh) for excess electricity

uranmaximum [27]

(A) The customer that owns a 3-kW system exports 120 kWh monthly to the grid will have the following bills for both companies:

For ZG&E that collects $3 per kWh on a monthly basis, the monthly bill will be

$120kWh\times\frac{\$3}{1kWh}=\$360$

For Ready Edison that collects $0.06 per kWh exported energy monthly, the computation of bill will be

$\$20+(120kWh\times\frac{\$0.06}{1kWh})=\$27.2$

(B) The customer that owns a 5-kW system exports 300 kWh monthly to the grid will have the following bills for both companies:

For ZG&E that collects $3 per kWh on a monthly basis, the monthly bill will be

$300kWh\times\frac{\$3}{1kWh}=\$900$

For Ready Edison that collects $0.06 per kWh exported energy monthly, the computation of bill will be

$\$20+(300kWh\times\frac{\$0.06}{1kWh})=\$38$

4 0

1 year ago

Machine 1 can complete a task in x hours while an upgraded machine (machine 2) needs 9 fewer hours. The plant manager knows the

lara31 [8.8K]

The (0, 3] is taken out of the picture leaving you with B.

We have given that,

Machine 1 can complete a task in x hours while an upgraded machine (machine 2) needs 9 fewer hours.

We have to determine the,

The plant manager knows the two machines will take at least 6 hours, as represented by the inequality

after you find the intervals.

you also need to consider that the plant manager knows the two machines will take at least 6 hours.

so (0, 3] is taken out of the picture leaving you with B.

To learn more about the inequality visit:

brainly.com/question/24372553

#SPJ1

4 0

2 years ago

A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be

irga5000 [103]

Answer:

The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r.

Step-by-step explanation:

Let $C = (h,k)$ the coordinates of the center of the circle, which must be transformed into $C'=(h', k')$ by operations of translation and reflection. From Analytical Geometry we understand that circles are represented by the following equation:

$(x-h)^{2}+(y-k)^{2} = r^{2}$

Where $r$ is the radius of the circle, which remains unchanged in every operation.

Now we proceed to describe the series of operations:

1) Center of the circle is translated 4 units to the right (+x direction):

$C''(x,y) = C(x, y) + U(x,y)$ (Eq. 1)

Where $U(x,y)$ is the translation vector, dimensionless.

If we know that $C(x, y) = (h,k)$ and $U(x,y) = (4, 0)$ , then:

$C''(x,y) = (h,k)+(4,0)$

$C''(x,y) =(h+4,k)$

2) Reflection over the x-axis:

$C'(x,y) = O(x,y) - [C''(x,y)-O(x,y)]$ (Eq. 2)

Where $O(x,y)$ is the reflection point, dimensionless.

If we know that $O(x,y) = (h+4,0)$ and $C''(x,y) =(h+4,k)$ , the new point is:

$C'(x,y) = (h+4,0)-[(h+4,k)-(h+4,0)]$

$C'(x,y) = (h+4, 0)-(0,k)$

$C'(x,y) = (h+4, -k)$

And thus, $h' = h+4$ and $k' = -k$ . The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r.

4 0

3 years ago