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topjm [15]
2 years ago
5

Find the surface area of the cube (above) using its net (below).

Mathematics
1 answer:
lana66690 [7]2 years ago
8 0

\mathsf \green{ {96 \: units}^{2} }

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What is the midpoint of the segment shown below?
kolbaska11 [484]

The midpoint of the segment is (-15/2, -15/2)

<h3>How to determine the midpoint?</h3>

The complete question is in the attached image

The points are given as:

(-8, -7) and (-7, -8)

The midpoint is calculated as:

(x,y) = 1/2 * (x1 + x2, y1 + y2)

So, we have:

(x,y) = 1/2 * (-8 - 7, -7 - 8)

Evaluate the difference

(x,y) = 1/2 * (-15, -15)

Evaluate the product

(x,y) = (-15/2, -15/2)

Hence, the midpoint of the segment is (-15/2, -15/2)

Read more about midpoints at:

brainly.com/question/4747771

#SPJ1

8 0
1 year ago
if the ratio of matts age to carlys age is 2/3, in ten years the ratio will be 4/5. how old is matthew?
Dima020 [189]
Matthew should be 14 yrs old
7 0
3 years ago
Solve Equation<br> 1. 6 - 4x = 6x - 8x + 2
Helga [31]

Answer:

X=2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

6−4x=6x−8x+2

6+−4x=6x+−8x+2

−4x+6=(6x+−8x)+(2)(Combine Like Terms)

−4x+6=−2x+2

−4x+6=−2x+2

Step 2: Add 2x to both sides.

−4x+6+2x=−2x+2+2x

−2x+6=2

Step 3: Subtract 6 from both sides.

−2x+6−6=2−6

−2x=−4

Step 4: Divide both sides by -2.

−2x/−2=−4/−2

Step 5 :Answer

X=2

LEAVE A LIKE IF THIS BELPED PLEASE.

4 0
3 years ago
8. H={all numbers of the form 3n+1, for n a natural number} under multiplication?
poizon [28]

Answer and Step-by-step explanation:

H= {all numbers of the form 3n+1, for n natural number} under multiplication:

Sol: all number of the form 3n+1, for n natural number so, put n=2, 3(2) +1 = 7, which is a natural number. A natural number under multiplication does not form a group because its inverse does not exist.

J= {all number of the form 3n+2, for n natural number} under multiplication:

Sol: all the number of the form 3n+2, n is the natural number does not form a group under multiplication because the identity element does not form in this set, and inverse does not exist.

K= {perfect squares of integers} under addition:

Sol: perfect square of integers under addition does not form a group because the inverse does not exist. For example, for any element x, inverse (-x) does not exist because of a square integer.

L= {perfect squares of integers} under multiplication:

Sol: a set of the perfect square of integers under multiplication is not a set, because it does not have the inverse property

M= {all numbers of the form 2, for n natural number} under addition:

Sol: natural number in the form of 2n, n is a natural number under addition is not a group as it does not have identity property. Identity property, under addition, is zero.

N= {all number of the form 2n, n is natural number} under multiplication:

All number of the form 2n, n is the natural number under multiplication is not a group. Because its inverse does not exist. For example, an element x belongs to a natural number; its inverse (1/x) does not exist in this set.

8 0
2 years ago
ANSWER ONLY IF YK IT IM GIVING CORRECT BRAINLIEST
wariber [46]

Answer:

-5(3x^3-1)

Step-by-step explanation:

-15x^3+5

Factor out -5

-5(3x^3-1)

4 0
3 years ago
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