Answer:
Use the distance formula on both points AC and AB.
<em>Distance formula is this</em><em>:</em>
<em>\begin{gathered}d=\sqrt{(x2-x1)^2+(y2-y1)^2} \\\\d=\sqrt{(1--5)^2+(8--7)^2} \\\\d=\sqrt{(6)^2+(15)^2} \\\\d=\sqrt{36+225} \\\\d=\sqrt{261} \\\\\end{gathered}d=(x2−x1)2+(y2−y1)2d=(1−−5)2+(8−−7)2d=(6)2+(15)2d=36+225d=261</em>
Distance for AC is 16.16
Now do the same with the numbers for AB and get the distance of 5.39
2. To get the area, use the formula 1/2 x base x height
AB is the base and AC is the height.
1/2 x 16.16 x 5.39 = 43.55
the answer is 43.5
Answer:
x ≥ 1 (how to graph is listed below)
Step-by-step explanation:
To find where we need to plot the line, we first need to solve the inequality for x:
-2x - 3 ≤ -5
(Add three to both sides)
-2x ≤ -2
(Divide both sides by -2, but we can't forget that whenever we multiple or divide by a negative number, the sign flips!)
x ≥ 1
To graph this on the number line, you would put a dot on the 1 and fill it in completely (you fill in the dot for a "___ and equal to" sign. ex. ≥, ≤)
Then you would make an arrow from the dot to the right on the number line (this is because x must be greater than or equal to 1, so it must be facing in that direction)
Answer:
the min is 53 the max is 90 median is 65 first quartile is 60 and the third quartile is 82
Step-by-step explanation:
