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sineoko [7]
3 years ago
10

Find the area shaded in yellow. [ ? ] square units

Chemistry
1 answer:
slega [8]3 years ago
6 0

Answer:

A(yellow) = 52

Explanation:

A(yellow) = A(total) - A(red)

= 11×6 - 7×2

= 66 - 14

= 52

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What part of a circuit stops the current if it is open
eduard

Answer:

B is the correct answer

Explanation:

Just is

8 0
3 years ago
Write the equilibrium constant expression for the reaction below.
kodGreya [7K]

Answer:

Kc = [H₂S]² . [CH₄] / [ H₂O]⁴ . [CS₂]

Explanation:

The equilibrium constant indicates the % of the yield reaction and can shows where the reaction is going to be equilibrated.

It works with molar concentrations on the equilibrium and it does not consider the solids compounds

Kc also can be modified by the time of the reaction.

This reaction is:

CS₂ (g) + 4 H₂O(g) ⇌ CH₄ (g) + 2H₂S (g)

Kc = [H₂S]² . [CH₄] / [ H₂O]⁴ . [CS₂]

8 0
2 years ago
How many molecules of H2O are there in 1.0 g of H2O?
NISA [10]
Molar mass H₂O = 18.0 g/mol

number of moles :

1.0 / 18.0 => 0.055 moles

1 mole -------------- 6.02 x 10²³ molecules
0.055 moles --------  ? molecules

molecules = 0.055 x ( 6.02 x 10²³) / 1

molecules = 3.311x10²² / 1

= 3.311 x 10²² molecules

hope this helps!
8 0
2 years ago
The attraction of hydrogen to oxygen in a water molecule has unequal sharing of electrons, caused by a(n) _____.
zheka24 [161]

Answer:

c

Explanation:

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5 0
2 years ago
Read 2 more answers
A reaction mixture initially contains 0.86 atm NO and 0.86 atm SO3. Determine the equilibrium pressure of NO2 if Kp for the reac
dlinn [17]

Explanation:

Reaction equation for this reaction is as follows.

     NO(g) + SO_{3}(g) \rightarrow NO_{2}(g) + SO_{2}(g)

It is given that K_{p} = 0.0118.

According to the ICE table,

              NO(g) + SO_{3}(g) \rightarrow NO_{2}(g) + SO_{2}(g)

Initial:           0.86      0.86               0            0

Change:          -x          -x                 +x           +x

Equilibrium:  0.86 - x   0.86 - x         x           x

Hence, value of K_{p} will be calculated as follows.

           K_{p} = \frac{P_{NO_{2}} \times P_{SO_{3}}}{P_{NO} \times P_{SO_{3}}}

         0.0118 = \frac{x \times x}{(0.86 - x)^{2}}

             x = 0.084 atm

Thus, we can conclude that P_{NO_{2}} is 0.084 atm.

4 0
3 years ago
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