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gogolik [260]
3 years ago
13

Element "Z" has 2 naturally occurring isotopes with the following masses and natural abundances:

Chemistry
1 answer:
fiasKO [112]3 years ago
3 0

Answer: the atomic Mass of Z is 46.26

Explanation:Please see attachment for explanation

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Electromagnetic waves are used in many technological devices. Describe two examples of how energy from electromagnetic waves is
kykrilka [37]

Answer:

Electromagnetic waves are ubiquitous in nature (i.e., light) and used in modern technology—AM and FM radio, cordless and cellular phones, garage door openers, wireless networks, radar, microwave ovens, etc. These and many more such devices use electromagnetic waves to transmit data and signals.

Explanation:

i mean there's alot of stuff that have Electromagnetic waves in it i mean alot!

3 0
3 years ago
Which of these mixtures will MOST LIKELY result in soil? A) sand, clay, and heat B) sand, clay, and water C) sand, clay, heat, a
Wewaii [24]

Answer:

I think it should be C.

Explanation:

Because for a plant to start photosinthesis it need sun (heat is like the sun),water,and stuff that soil is made of (sand and clay) tell me if this is correct

Thanks

5 0
3 years ago
Read 2 more answers
How much potassium chloride, KCI, is produced during the decomposition of 100.0 grams of potassium chlorate KCIO3? Please show s
Ne4ueva [31]
Answer: the reaction will produce 15.3 g of
KCl.

explanation:
1. write the balanced equation.
2KClO
3
→
2KCl
+
3O
2

2. calculate the moles of
KClO
3
.
Moles of KClO
3
=
25.0
g KClO
3
×
1 mol KClO
3
122.55
g KClO
3
=
0.2046 mol KClO
3

3. calculate the moles of
KCl
.
Moles of KCl
=
0.2046
mol KClO
3
×
2 mol KCl
2
mol KClO
3
=
0.2046 mol KCl

4. calculate the mass of
KCl
.
Mass of KCl
=
0.2046
mol KCl
×
74.55 g KCl
1
mol KCl
=
15.3 g KCl
4 0
3 years ago
If you have 10cm of snow with a volume of 40mL and a density of 0.5 g/mL how many inches of rain is this?
Lelu [443]

Density is the mass of compound divided by its volume can be shown as follows:

d = 0.5 g /mL = m /V = m /40 = 0.5

m = 20 g

40 mL of snow having 20 g of mass calculated from density.

Now, 10 cm of snow = 3.93 inches = 20 g  

As, 10 inches of rain will produce 11 inches of ice as the volume of ice is bigger than rain water.

10 inches rain = 11 inches snow

3.93 inches of snow produced by  

= (3.93 * 10) /11 = 3.57 inches rain.

Thus, 3.57 incehs of rain produces by 10 cm snow.

4 0
3 years ago
Particles of light are known as​
Mashcka [7]

HEY DEAR..

The particles of light known as photon.

HOPE ITS HELPFULL

6 0
3 years ago
Read 2 more answers
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