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GarryVolchara [31]
2 years ago
12

1. Use your knowledge of valence electrons and how they affect bonds to figure out how carbon (Group 14) and oxygen (Group 16) w

ould be attached to one another. In carbon dioxide (CO2), how is the compound structured? (Use “–” to represent a single bond and “=” to represent a double bond.)(1 point)
A) O=C–O

B) O=C=O

C) C=O–O

D) C–O–O

2. Methane’s chemical formula is CH4. Is there a bond between any of the hydrogen atoms? Why or why not?(1 point)

A) Yes, there is because they form a long chain in order to all have stable outer energy shells.

B) Yes, there is because there are one too many hydrogen atoms for carbon to handle alone, so one hydrogen must bond with another.

C) No, there is not because carbon needs four bonds, so it bonds with each hydrogen atom; hydrogen only forms one bond.

D) No, there is not because it would form H2 instead of methane if hydrogen-bonded with itself.

3. In hydrogen peroxide (H2O2), which option best shows how the atoms are ordered?(1 point)

A) H–O–O–H

B) O–H–O–H

C) H–O–H–O

D) O–H–H–O
Chemistry
1 answer:
erik [133]2 years ago
5 0

From the fact that oxygen is in group 16 and carbon is in group 14, the structure of CO2 must be O=C=O. In methane, there is no bond between any of the hydrogen atoms. The structure of H2O2 is H–O–O–H.

Carbon is in group 14 hence it has four valence electrons and oxygen is in group 16 hence it has six valence electrons. This implies that each oxygen atom will share four electrons with carbon in a covalent bond to form the structure O=C=O.

In CH4, we know that carbon is tetravalent so it forms for bonds. Therefore, there is no bond between hydrogen atoms so it bonds with each hydrogen atom; hydrogen only forms one bond.

In H2O2, there is the peroxide ion that has the structure O-O. Hence, the correct structure of H2O2 is H–O–O–H.

Learn more: brainly.com/question/24775418

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In acid solution, water can add to the double bond of 2-butenedioic acid to form 2-hydroxysuccinic acid.
satela [25.4K]
So, what is the question?
6 0
2 years ago
Which of the following solids would not decompose on heating​
Gekata [30.6K]

Answer:

Anhydrous sodium carbonate is stable to heat and does not decompose even when it is heated to redness. This is because sodium carbonate salt on heating with acids react to release carbon dioxide.

5 0
2 years ago
How much heat in kj is released by burning 9.5 grams of methane?
tatyana61 [14]
Methane is the compound CH4, and burning it uses the reaction:

CH4 + O2 -> CO2 + H2O, which is rather exothermic. To find the heat released by burning a certain amount of the substance, you should look at the bond enthalpy of each compound, and then compare the values before and after the reaction. In methane, there are 4 C-H bonds, which have bond energy of 416 kj/mol, resulting in a total bond energy of 1664 kj/mol. O2 is 494 kj/mol. Therefore we have a total of 2080 kj/mol on the left side. On the right side we have CO2, which has 2 C=O bonds, each at 799 kj/mol each, resulting in 1598 kj/mol, and H2O has 2 O-H bonds, at 459kj/mol each, resulting in a total of 2516 kj/mol on the right hand side. Now, this may be confusing because the left hand side seems to have less heat than the right, but you just need to remember: making minus breaking, which results in a total change of 436kj/mol heat evolved.

Now it is a simple matter of find the mols of CH4 reacted, using n=m/mr.

n = 9.5/16.042 = 0.592195 mol

Therefore, if we reacted 0.592195 mol, and we produced 436 kj for one mol, the total amount of energy evolved was 436*<span>0.592195 kj, or 258.197 kj.</span>
7 0
3 years ago
What volume of 0.585 m ca(oh)2 would be needed to neutralize 15.8 l of 1.51 m hcl?
SpyIntel [72]
When the balanced reaction equation is:

2HCl(aq) + Ca(OH)2(aq) → CaCl2(aq) + 2H2O(l)

from the balanced equation, we can get the molar ratio between HCl & Ca(OH)2

2:1

∴ the volume of Ca(OH)2 = 15.8 L HCl * 1.51 m HCl * (1mol Ca(OH)2/ 2mol HCl) *                                           (1L ca(OH)2/0.585 mol Ca(OH)2 

                                          = 20.4 L
8 0
3 years ago
A 0.35 L balloon found at 19 C is heated in an oven to 250 C. What is the new volume of the balloon?
Svet_ta [14]

Answer:

V = 0.63 L

Explanation:

To solve this problem, we need to use the Charle's law which is a law that involves temperature and volume, assuming we have a constant pressure. The problem do not state that the pressure is being altered, so we can safely assume that the pressure is constant (Maybe 1 atm).

Now, as the pressure is constant, the Charle's law is the following:

V₁ / T₁ = V₂ / T₂   (1)   V is volume in Liter, and T is temperature in Kelvin.

Using this law with the given data, we solve for V₂:

V₂ = V₁T₂ / T₁

Before we use this expression, let's convert the temperatures to Kelvin:

T₁ = 19 + 273 = 292 K

T₂ = 250 + 273 = 523 K

Now, let's calculate the volume of the balloon:

V₂ = 0.35 * 523 / 292

<h2>V₂ = 0.63 L</h2>
5 0
3 years ago
Read 2 more answers
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