Pls help me answer this!

Name the following compound: CH3-CH2-CH2-CH2-CH3 CH3 CH3

stepan [7]

Answer:

Pentane

Explanation:

since we have in here CH3-CH2-CH2-CH2-CH3 5 Carbon atoms and 12 Hydrogen making it $C_{5} H_{12}$

6 0

3 years ago

Here is a list of ingredients for a simple cake:

cupoosta [38]

So really you only need to answer the first one because you have more than enough og everything. 2×(what)=14 then that will be your answer

3 0

3 years ago

15.89 percent carbon, 21.18 percent oxygen, and 62.93 percent osmium. what is the empirical formula

otez555 [7]

Answer:

OsCO or COOs

Explanation:

Data given

Carbon = 15.89 %

Oxygen = 21.18 %

Osmium = 62.93%

Empirical formula = ?

Solution:

First find the masses of each component

Consider total compound is 100g

As we now

mass of element = % of component

So,

15.89 g of C = 15.89 % Carbon

21.18 g of O = 21.18 % Oxygen

62.93 g of Os = 62.93% Osmium

Now convert the masses to moles

For Carbon

Molar mass of C = 12 g/mol

no. of mole = mass in g / molar mass

Put value in above formula

no. of mole = 15.89 g/ 12 g/mol

no. of mole = 1.3242

mole of C = 1.3242

For Oxygen

Molar mass of O = 16 g/mol

no. of mole = mass in g / molar mass

Put value in above formula

no. of mole = 21.18 g/ 16 g/mol

no. of mole =

mole of O = 1.3238

For Os

Molar mass of Os = 190 g/mol

no. of mole = mass in g / molar mass

Put value in above formula

no. of mole = 62.93 g/ 190 g/mol

no. of mole =

mole of Os = 1.3312

Now we have values in moles as below

C = 1.3242

O = 1.3238

Os = 1.3312

Divide the all values on the smalest values to get whole number ratio

C = 1.3242 /1.3238 = 1.0003

O = 1.3238 /1.3238 = 1

Os = 1.3312 /1.3238 = 1.0056

So all have round value 1 mole

C = 1

O = 1

Os = 1

So the empirical formula will be (OsCO) i.e. all 3 atoms in simplest small ratio

7 0

3 years ago

What must molecules do to react?

katrin2010 [14]

B:Molecules must collide.
Why: They have to collide so the chemical bonds can break.

3 0

3 years ago

Read 2 more answers

Which of the following correctly compares the radii of Cl and Cl−?

nignag [31]

Answer:

Cl has a smaller radius than Cl− because Cl− has an expanded electron cloud.

Explanation:

Definition of atomic radii:

The atomic radius is the distance between center of two bonded atoms.

Trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase.The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases.

Trend along group:

In group by addition of electron atomic radii increase from top to bottom due to increase in atomic number and addition of extra shell.

In this way Cl⁻ will have the largest atomic radii because one extra electron is added and electronic cloud more expanded as compared to neutral atom.

7 0

3 years ago