Use Pythagorean Theorem:
28^2+15^2=c^2
1009=c^2
Square both sides:
31.8
A
Answer:
a. 49.5 and 54.5
Step-by-step explanation:
Class interval is a range of a value that is used to group data into equal size for easy analysis and representation of the data. It is applicable in the divisions of a histogram or bar chart into classes. Examples of class interval are 50-54, 55-59, 60-64, 65-69, 70-74 etc.
Class limit is the minimum and maximum value the class interval may contain. The minimum value is called the lower class limit and the maximum value is called the upper class limit. For class interval 50-54, the lower class limit is 50 and the upper class limit is 54.
Class boundaries are the numbers used to separate classes. It is the real limits of a class. For non-overlapping classes, the lower class boundary of each class is calculated by subtracting 0.5 from the lower class limit. The upper class boundary of each class is calculated by adding 0.5 to the upper class limit. Example: For class interval 50-54, the lower class boundary is 49.5 and the upper class class boundary is 54.5
Considering the question given, to get the real limits of the interval 50-54, 0.5 is subtracted from the lower class limit to give 49.5. Also, 0.5 is added to the upper class limit to give 54.5.
Answer:
The point-slope form of the line is:
Hence, option B is correct.
Step-by-step explanation:
We know the point-slope form of the line equation is
where
- m is the slope of the line
Given
The slope m = 4
From the graph, we can take the point (-3, -4)
So, in our case:
(x₁, y₁) = (-3, -4)
m = 4
now substituting m = 4 and (x₁, y₁) = (-3, -4) in the point-slope form of the line equation
Therefore, the point-slope form of the line is:
Hence, option B is correct.
- The graph of the line is also attached.
I believe it's 7 hope it helps
