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strojnjashka [21]
3 years ago
9

While training for an Ironman competition, Johnson swam 0.86 km, biked for 22.4 km, and ran 4.25 km. Johnson completed this rout

ine twice a week. How far did Johnson travel in one week while training, in meters?
Mathematics
1 answer:
igomit [66]3 years ago
3 0

Answer:

55020 metres

Step-by-step explanation:

Johnson swam 0.86 km, biked for 22.4 km, and ran 4.25 km. He did this twice a week.

To find the total distance traveled in one week in metres, we first add up the distances and multiply by 2 and then convert to metres.

The sum of the distances is:

0.86 + 22.4 + 4.25 = 27.51 km

Multiply by 2:

27.51 * 2 = 55.02 km

1 km = 1000 metres

55.02 km = 55.02 * 1000 = 55020 metres

He traveled 55020 metres while training.

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(A)Segment EF, segment FG, segment GH, and segment EH are congruent

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<u>Step 1</u>

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

<u>Step 2</u>

Using the distance formula

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

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Given G(4,3), H(1,0)

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<u>Step 3</u>

Segment EF ,E (−2, 3), F (1, 6)

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Segment GH, G (4, 3), H (1, 0)

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Segment EH, E(−2, 3), H (1, 0)

Slope of |EH|= \frac{0-3}{1+2} =\frac{-3}{3}=-1

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| =\frac{3-6}{4-1} =\frac{-3}{3}=-1

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Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

<u>Step 6</u>

<u>Segment EF, segment FG, segment GH, and segment EH are congruent. </u>

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

<u>Step 7</u>

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

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