Answer:
c.13.7mi, A=33.3°, B=56.7°
When all the other numbers you have are lower
Answer:
Density of the material is 5 grams per cubic centimeter.
Step-by-step explanation:
The answer is required to be given in grams per cubic centimeter.
So we should first convert the values to match the units.
Mass is given as 2500 grams so we don't need to change the units.
Volume is given in cubic centimeters. So we don't need to change the units.
Density = [ Mass of the material / Volume of the Solvent]
=2500 grams / 500 cubic centimeters
=5 grams per cubic centimeter
Answer:

Step-by-step explanation:
We want to find a formula for <em>s</em> in terms of <em>a, b, </em>and cos(x).
Let the point where <em>s</em> intersects AB be D.
Notice that <em>s</em> bisects ∠C. Then by the Angle Bisector Theorem:

We can find BD using the Law of Cosines:

Likewise:

From the first equation, cross-multiply:

And square both sides:

Substitute:

Distribute:

Simplify:

Divide both sides by <em>s </em>(<em>s</em> ≠ 0):

Isolate <em>s: </em>

Factor:

Therefore:

Factor:

Simplify. Therefore:

Answer:
1. Cos θ = 6√2 / 11
2. Tan θ = 7 / 6√2
3. Cosec θ = 11 / 7
4. Sec θ = 11 / 6√2
5. Cot θ = 6√2 / 7
Step-by-step explanation:
From the question given above, the following data were obtained:
Sine θ = 7 / 11
Next, we shall determine the adjacent of the right triangle. This can be obtained as follow:
Sine θ = 7 / 11
Sine θ = Opposite / Hypothenus
Opp = 7
Hypo = 11
Adj =?
Hypo² = Opp² + Adj²
11² = 7² + Adj²
121 = 49 + Adj²
Collect like terms
Adj² = 121 – 49
Adj² = 72
Take the square root of both side
Adj = √72
Adjacent = 6√2
1. Determination of Cos θ
Adjacent = 6√2
Hypothenus = 11
Cos θ =?
Cos θ = Adjacent / Hypothenus
Cos θ = 6√2 / 11
2. Determination of Tan θ
Opposite = 7
Adjacent = 6√2
Tan θ =?
Tan θ = Opposite / Adjacent
Tan θ = 7 / 6√2
3. Determination of Cosec θ
Sine θ = 7 / 11
Cosec θ =?
Cosec θ = 1 ÷ Sine θ
Cosec θ = 1 ÷ 7 / 11
Cosec θ = 1 × 11/7
Cosec θ = 11/7
4. Determination of Sec θ
Cos θ = 6√2 / 11
Sec θ =?
Sec θ = 1 ÷ Cos θ
Sec θ = 1 ÷ 6√2 / 11
Sec θ = 1 × 11 / 6√2
Sec θ = 11 / 6√2
5. Determination of Cot θ
Tan θ = 7 / 6√2
Cot θ =?
Cot θ = 1 ÷ Tan θ
Cot θ = 1 ÷ 7 / 6√2
Cot θ = 1 × 6√2 / 7
Cot θ = 6√2 / 7