3 years ago

How the points are placed in graphing linear inequalities?

Mathematics

1 answer:

Yanka [14]3 years ago

5 0

Answer:

Plot the line y = 2x - 3 and the portion above the line will satisfy the inequality.

You might be interested in

Expand and simplify (y-3)³

Tanya [424]

Answer:

Expanded: (y-3)(y-3)(y-3)

Simplified: $y^{3}-9y^{2}+27y-27$

Step-by-step explanation:

Expanded: (y-3)(y-3)(y-3)

Simplified:

$y^{2} -3y-3y+9(y-3)\\y^{2} -6y+9(y-3)$

$y^{3} -3y^{2}-6y^{2} +18y+9y-27$

$y^{3}-9y^{2} +27y-27$

5 0

3 years ago

Find the root of 11+2square30

EleoNora [17]

$\\ \sf\longmapsto \sqrt{11+2^230}$

$\\ \sf\longmapsto \sqrt{11+4(30)}$

$\\ \sf\longmapsto \sqrt{11+120}$

$\\ \sf\longmapsto \sqrt{131}$

$\\ \sf\longmapsto 11.3$

5 0

2 years ago

- 1 solve the equation - m - 7 = 5 3

Eduardwww [97]

The answer is 60 because were subtracting in the equation but to find m we need to the opposite which is to add 53 plus 7 which is 60. To check your answer do 60-7 equals 53

3 0

3 years ago

Read 2 more answers

The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula mc

Gnoma [55]

Given that the orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula P = a^(3/2). If Saturn’s orbital period is 29.5 years, then 29.5 = a^(3/2) a = (29.5)^(2/3) = 9.547 Therefore, Saturn's distance from the sun is 9.547 astronomical units.

7 0

3 years ago

Read 2 more answers

I)3 by x-1=4 by x+1 ii)X by 2-Xby3=2

Lena [83]

Answer:

Hey blinkkkkkkkkkkkkk

3 0

2 years ago