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3 years ago

How the points are placed in graphing linear inequalities?

Mathematics

1 answer:

Yanka [14]3 years ago

5 0

Answer:

Plot the line y = 2x - 3 and the portion above the line will satisfy the inequality.

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Use the equation y=3x-8 to find y when x=8

Stels [109]

Answer: X = 8/3

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the solution of the equation?

nadya68 [22]

Answer:

q = 4

Fully simplifying this equation gives you answer (A) q = 4

Hope this helps!

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3 years ago

Write a system of two equations in two variables to solve the problem. when fully extended, a ladder is 28 feet in length. if th

Alisiya [41]

Let the base of the ladder be x ft and the extension be y ft.

"when fully extended, a ladder is 28 feet in length."

means: x+y=28

"the extension is 4 feet shorter than the base"

means: y=x-4, that is x-y = 4, (taking y to the side of x, and -4 to the other side of x and y)

thus, we have the system of equations:

1) x+y= 28

2) x-y=4

adding the 2 equations, we have:

(x+y)+(x-y)=28+4

2x=32

x=32/2=16

x+y=28, so 16+y=28, thus y=12

Answer: Base: 16, Extension 12

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3 years ago

Based only on the information given in the diagram, it is guaranteed that JKL ~ WXY.

Alika [10]

Answer:

Option A True

Step-by-step explanation:

we know that

The sum of the internal angles of the triangle is equal to $180\°$

In the triangle JKL

m∠L= $180\°-90\°-27\°=63\°$

The measurements of the angles of triangle JKL are $27\°-90\°-63\°$

In the triangle WXY

m∠W= $180\°-90\°-63\°=27\°$

The measurements of the angles of triangle WXY are $27\°-90\°-63\°$

therefore

Triangle JKL and triangle WXY are similar by AAA ( The AAA postulate states that if you can prove that all three angles of two triangles are congruent, you can prove the two triangles are similar)

6 0

3 years ago

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Select the quadratic equation that has roots x=8 and x=-5

stellarik [79]

Step-by-step explanation:

Since, x=8 and x=-5 are the roots.

Therefore, (x - 8) & (x - 5) will be factors.

Hence, required quadratic equation can be given as:

$(x - 8)(x - 5) =0 \\ \\ \therefore {x}^{2} + ( - 8 - 5) x+ ( - 8) \times ( - 5) = 0 \\ \\ \therefore {x}^{2} + ( - 13) x+ 40= 0 \\ \\ \huge \red{ \boxed{ \therefore {x}^{2} - 13x+ 40= 0 }} \\ is \: the \: required \: quadratic \: equation.$

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3 years ago