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3 years ago

What is f+0.3<-1.7 please help

Mathematics

2 answers:

Verdich [7]3 years ago

7 0

If you need further explanation, i may provide you with it, but the answer is: f < - 2

Hope this helped :)

satela [25.4K]3 years ago

5 0

F<-2. You just subtract 0.3 to -1.7

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The rainfall for one year was 35.8 inches. What was the approximate rainfall per month

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peter and his four brothers combined all of their money to buy a video game. if 20%of the total money is peters and $12.00 of th

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Answer:

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3 years ago

Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
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Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
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$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
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$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

6 0

3 years ago

PLEASE HELP!! WILL GIVE BRAINLIEST!!!!

Arturiano [62]

Answer:

y=1

Step-by-step explanation:

Given function y=m(x)

The question is to find the y value where x equals -2 so the easiest way is to plus x=-2 in the graph, we can get y=1.

Hopefully this helps, if you have any questions please feel free to ask them in the comment section below, I'll be more than happy to answer!

5 0

3 years ago

27^-2/3 A. 9 B. 1/9 C. -1/9 D. -9

geniusboy [140]

27^-2/3
= (3^3)^-2/3
= 3^-2
= 1/3^2
= 1/9

answer
B. 1/9

5 0

3 years ago