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Alex Ar [27]
3 years ago
9

the quadrilateral ABCD on a coordinate plane has the following characteristics. AD can be represented by the equation y=-3x wher

e -1 < x < 0. BC can be represented by the equation y=-3x+11 where 2 < x < 3. Cd has the coordinates C(2,5) and D(-1,3). in order for ABCD to be a parallelogram, which of the following coordinates correspond to AB.
Mathematics
1 answer:
vovangra [49]3 years ago
5 0
The coordinates of point A will be (0, 0) and the coordinates of B will be (3, 2).

To find these coordinates you have to graph the points and line segments. You will see that the 2 line segments start at points C and D and move down to the right. The endpoints of these segments will form your parallelogram.
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Draw the image of the following segment after a dilation centered at the origin with a scale factor of 2/3
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Answer:

Step-by-step explanation:

Let the ends of the given segment are A and B.

Coordinates of A → (8, 6)

Coordinates of B → (12, 12)

If a point (x, y) is dilated by a scale factor 'k' about the origin, rule to be followed,

(x, y) → (kx, ky)

If k = \frac{2}{3}

(x, y) → (\frac{2}{3}x, \frac{2}{3}y)

By this rule coordinates of the image points of A and B will be,

A(8, 6) → A'(\frac{2\times 8}{3},\frac{2\times 6}{3})

           → A'(5.3, 4)

B(12, 12) → B'(\frac{12\times 2}{3}, \frac{12\times 2}{3})

             → B'(8, 8)

Now we can get the image of segment AB after dilation by a scale factor of \frac{2}{3}.

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What is the equivalent expression after this is simplified
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Answer: -6 - 5k

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