C = total number of candy
.4(c) = 8 pieces of candy
Divide c by .4: c= 20
20-8=12
Ed has 12 pieces of candy at home
Answer:
1) is not possible
2) P(A∪B) = 0.7
3) 1- P(A∪B) =0.3
4) a) C=A∩B' and P(C)= 0.3
b) P(D)= 0.4
Step-by-step explanation:
1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4
2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by
P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7
P(A∪B) = 0.7
3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3
4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then
P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3
the probability for the event D=a student has exactly one of the cards is
P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4
I think its A not sure though
Answer:
There were 240 more credit card sales than cash sales.
Step-by-step explanation:
By using the ratio 8:3 I was able to determine that if there were 144 cash sales that would mean that there would be 384 credit card sales. However, the question asks "How many <u>more</u> credit card sales were there than cash sales?" Meaning that we need to find the difference. 384-144= 240.
This means that there were 240 <u>more</u> credit card sales than cash sales.
Hope this helped! If you have any questions about what I did please comment!
And if this helped please mark brainliest!
Have a great day!!
744/1000 would be your answer
