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3 years ago

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A square photo-display board is made up of 60 rows fo 60 photo each. Area of each square photo is 4 square inches. How long is e

ach side of the display board

1 answer:

tankabanditka [31]3 years ago

4 0

224 is the answer to the question

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What’s the Answer to this

9966 [12]

Answer: the answer to this is 5n

5 0

3 years ago

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Please can somebody help me with this question please...!

olga55 [171]

Since you are given that the student registered early, the total number you deal with is all students who registered early.

211 + 329 = 540

number of undergraduates who registered early = 211

Among students who registered early:

p(undergraduate) = 211/540

4 0

3 years ago

A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na

ira [324]

Answer:

Approximately $58.2\; \text{nautical miles}$ (assuming that the bearing is ${\rm S$29^{\circ}$W}$ .)

Step-by-step explanation:

Let $v$ denote the speed of the ship, and let $t$ denote the duration of the trip. The magnitude of the displacement of this ship would be $v\, t$ .

Refer to the diagram attached. The direction ${\rm S$29^{\circ}$W}$ means $29^{\circ}$ west of south. Thus, start with the south direction and turn towards west (clockwise) by $29^{\circ}$ to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of $v\, t$ . The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly $29^{\circ}$ .

Since the hypotenuse is of length $v\, t$ , the dashed line segment opposite to the $\theta = 29^{\circ}$ vertex would have a length of:

$\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}$ .

Substitute in $\begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned}$ and $t = 6\; \text{hour}$ :

$\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}$ .

7 0

2 years ago

Rewrite the equation below so that it does not have fractions.

Leviafan [203]

9514 1404 393

Answer:

8x -24 = 9y

Step-by-step explanation:

We assume your equation is ...

2/3x -2 = 3/4y

__

Fractions can be eliminated by multiplying the equation by the least common denominator of the fractions.

LCM(3, 4) = 12

Multiplying the equation by 12 gives you ...

12(2/3x -2) = 12(3/4y)

8x -24 = 9y

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3 years ago

What is the length of the second base of a trapezoid if the length of one base is 27 and the length of the mid-segment is 19? sh

stira [4]

Length of the mid-segment = (long base + short base) / 219 = (27 + short base) / 219 - (27 / 2) = short base / 2Multiplying both sides by 238 -27 = short baseshort base = 11
Source:http://www.1728.org/quadtrap.htm

3 0

3 years ago

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