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gogolik [260]
3 years ago
11

Which of the following shows the general formula for factoring the difference of cubes?

Mathematics
1 answer:
Tcecarenko [31]3 years ago
7 0

Answer:

(a - b)(a² + ab + b²)

Step-by-step explanation:

The difference of cubes is expressed as:

a³-b³

Using trial and error:

a³-b³

Check  (a - b)(a² + ab + b²)

Expand

(a - b)(a² + ab + b²)

= a(a²)+a(ab)+a(b²)-a²b-ab²-b³

= a³+a²b+a(b²)-a²b-ab²-b³

Collect the like terms

= a³+a²b-a²b+ab²-ab²-b³

= a³-b³

Hence the required option is

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Answer:

A. 23+(6-1)x-3

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Step-by-step explanation:

a) Nth term = F + (N - 1) x D, where F=First term, N=Number of terms, D=Common difference

6th row = 23 + (6 - 1) x -3

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b) Sum = N/2[2F + (N - 1) x D]

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