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jeka57 [31]
3 years ago
8

Help ? I don’t know how to do it

Mathematics
1 answer:
ryzh [129]3 years ago
4 0
I think 60°
these angles are very confusing sorry!
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What is the absolute davatation round to the nearest tenth for 6.3, 6.4, 6.5, 6.6, 6.8. 6.8, 7.5?
WITCHER [35]
Let's find the mean of all the values first.
6.3+6.4+6.5+6.6+6.8+6.8+7.5= 46.9
Let's divide by the number of values.
46.9÷7=
6.7
Now let's find the distance that each number is away from 6.7 and find the mean of those numbers.
0.4+0.3+0.2+0.1+0.1+0.1+0.8=
.2857
≈ 0.3
So, the absolute deviation is 0.3.
8 0
3 years ago
Read 2 more answers
ASAP HELP! BRAINLIEST! can someone help me with this? i need work shown. will mark brainliest!
ki77a [65]

Answer:

  4x^2 +12x +44 remainder 161x +84

Step-by-step explanation:

At each step, the quotient term is the ratio of the leading dividend term to the leading divisor term. The first quotient term, for example, is ...

  (4x^4)/(x^2) = 4x^2

The quotient term found this way is multiplied by the divisor and subtracted from the dividend. The difference is the new dividend and the process repeats.

You're done when the degree of the dividend is less than the degree of the divisor. This remainder can be expressed as a fraction with the divisor as the denominator.

  \dfrac{4x^4+5x-4}{x^2-3x-2}=4x^2+12x+44+\dfrac{161x+84}{x^2-3x-2}

5 0
2 years ago
The sutton police department must write, on average, 6 tickets a day to keep department revenues at budgeted levels. suppose the
lakkis [162]
The Poisson distribution defines the probability of k discrete and independent events occurring in a given time interval.
If λ = the average number of event occurring within the given interval, then
P(k \, events) = e^{-\lambda } ( \frac{\lambda ^{k}}{k!} )

For the given problem,
λ = 6.5, average number of tickets per day.
k = 6, the required number of tickets per day
The Poisson distribution is
P(k \, tickets/day)=e^{-6.5} ( \frac{6.5 ^{k}}{k!} )
The distribution is graphed as shown below.

Answer: 
The mean is λ = 6.5 tickets per day, and it represents the expected number of tickets written per day.
The required value of k = 6 is less than the expected value, therefore the department's revenue target is met on an average basis.

8 0
3 years ago
2 women and 7 girls can do a peice of work in 4 days.4 women and 4 girls can do the same work in 3 days. How long would it take
svetlana [45]

Answer:

x: work a woman can do in 1 day

y: work a girl can do in 1  day

Then

2x + 7y =1/4

4x + 4y =1/3

4x + 14y =2/4 (1)

4x + 4y  =1/3 (2)

=> Let (1) - (2), 10y =2/4-1/3 <=>10y = 1/6 <=> y = 1/(6x10) = 1/60 (work)

=> From (2),4x = 1/3 - 4x1/60 => 4x = 16/60 => x = 4/60 (work)

=> 1 day, a woman and a girl can do: 1/60+4/60 = 5/60 =1/12 (work)

Then, the day required for a woman and a girl to complete work: 12 days

3 0
3 years ago
What's the answer to this ?? Need help
Veseljchak [2.6K]
It goes by 3s so I think its 1.2
5 0
3 years ago
Read 2 more answers
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