Let's find the mean of all the values first.
6.3+6.4+6.5+6.6+6.8+6.8+7.5= 46.9
Let's divide by the number of values.
46.9÷7=
6.7
Now let's find the distance that each number is away from 6.7 and find the mean of those numbers.
0.4+0.3+0.2+0.1+0.1+0.1+0.8=
.2857
≈ 0.3
So, the absolute deviation is 0.3.
Answer:
4x^2 +12x +44 remainder 161x +84
Step-by-step explanation:
At each step, the quotient term is the ratio of the leading dividend term to the leading divisor term. The first quotient term, for example, is ...
(4x^4)/(x^2) = 4x^2
The quotient term found this way is multiplied by the divisor and subtracted from the dividend. The difference is the new dividend and the process repeats.
You're done when the degree of the dividend is less than the degree of the divisor. This remainder can be expressed as a fraction with the divisor as the denominator.

The Poisson distribution defines the probability of k discrete and independent events occurring in a given time interval.
If λ = the average number of event occurring within the given interval, then

For the given problem,
λ = 6.5, average number of tickets per day.
k = 6, the required number of tickets per day
The Poisson distribution is

The distribution is graphed as shown below.
Answer:
The mean is λ = 6.5 tickets per day, and it represents the expected number of tickets written per day.
The required value of k = 6 is less than the expected value, therefore the department's revenue target is met on an average basis.
Answer:
x: work a woman can do in 1 day
y: work a girl can do in 1 day
Then
2x + 7y =1/4
4x + 4y =1/3
4x + 14y =2/4 (1)
4x + 4y =1/3 (2)
=> Let (1) - (2), 10y =2/4-1/3 <=>10y = 1/6 <=> y = 1/(6x10) = 1/60 (work)
=> From (2),4x = 1/3 - 4x1/60 => 4x = 16/60 => x = 4/60 (work)
=> 1 day, a woman and a girl can do: 1/60+4/60 = 5/60 =1/12 (work)
Then, the day required for a woman and a girl to complete work: 12 days
It goes by 3s so I think its 1.2