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vovangra [49]
3 years ago
11

What is the distance between the y-intercepts of the lines? Adding a picture please help

Mathematics
1 answer:
DerKrebs [107]3 years ago
6 0

The equation of a line is:

y = mx + c

The m is the gradient of the line, and the c is the y-intercept of the line

That means that the y-intercept of [y = -4x + 3]  is 3

and the y-intercept of [y = -4x + 4] is 4

So the distance between the two y-intercepts is:

4 - 3 = <u>1</u>

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The radius AND height of a cylinder are each doubled. What is the new volume?
Naya [18.7K]

The volume of a cylinder is given by

V = \pi hr^2

Let h\mapsto 2h and r\mapsto 2r

The new volume becomes

V = \pi(2h)(2r)^2 = \pi\cdot 2h \cdot 4r^2 = 8\pi hr^2

So, the new volume is 8 times the original volume. In fact, volume scales linearly with the height and quadratically with the radius.

7 0
3 years ago
A grasshopper jumps straight up from the ground with an initial vertical velocity of 8 feet per second. After how many seconds w
vlabodo [156]

Answer:

Problem 1 : After 0.25 s

Problem 2 : The squirrel doesn't reach the ground before the nut

Step-by-step explanation:

Problem 1

This is a standard physics problem

The equation that defines the movement of the grasshopper given the initial velocity, and the acceleration is the following

Distance =  Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 0, because the grasshopper is on the ground and we choose the reference system there)

Vo is the initial velocity = 8 feet/sec

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 = - 32.174 feet per second per second.)

t is the time

We substitute in the equation, and solve for t (time)

Distance =  Do + Vo*t + 0.5*a*t^2

(1 foot)=  (0)+ (8 feet/s)*t + 0.5*(-32.174 feet/s^2)*t^2

Solving this equation, we get that

t = 0.25 s

Problem 2

This problem is similar to the previous one

We apply the same formula

D =  Do + Vo*t + 0.5*a*t^2

But in this case, we are going in the opposite direction, and we have an initial distance.

Do = 27 feet

Vo is the initial velocity of the nut = -6 feet/s

D = 0  (Ground)

We substitute in the equation, and solve for t (time)

(0) =  (27) + (-6 feet/s)*t + 0.5*(-32 feet/s^2)*t^2

t = 1.125 s  <  2s

The nut reaches ground in 1.125 s, so the squirrel doesn't reach the ground before the nut

4 0
3 years ago
Which equations are related equations to x + 5 = 34?
myrzilka [38]

Answer:

the answer is 5=34−x and x=34−5

Step-by-step explanation:

i just got finished taking the test in 7th grade k12

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3 years ago
There are approximately 1 1/2 kilometers in one mile. Approximately how many kilometers are in 6 miles​?
adelina 88 [10]
1.5 times 6 is equal to 9. So the answer is 9 kilometers
6 0
3 years ago
5. Ms. Peterson earns $18 per hour as a softball team coach and $25 per hour as a math tutor. Last week, she worked
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Answer: 18,20

Step-by-step explanation:

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2 years ago
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