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3 years ago

Solve the equation for x, where x is a real number (5 points): -2x^2 + 5x + 2 = -3

1 answer:

5 0

Add 3 to both sides so that the equation becomes -2x^2 + 5x + 5 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
                              x = [ -b ± √(b^2 - 4ac) ] / (2a)
                              x = [ -5 ± √(5^2 - 4(-2)(5)) ] / ( 2(-2) )
                              x = [-5 ± √(25 - (-40) ) ] / ( -4 )
                              x = [-5 ± √(65) ] / ( -4)
                              x = [-5 ± sqrt(65) ] / ( -4 )
                              x = 5/4 ± -sqrt(65)/4
The answers are 5/4 + sqrt(65)/4 and 5/4 - sqrt(65)/4..

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Expand.<br> Your answer should be a polynomial in standard form.<br> (3c + 2)(c^2-6c-4)

evablogger [386]

Answer:

After expanding the polynomial $(3c + 2)(c^2-6c-4)$ we get $3c^3-16c^2-24c-8$

Step-by-step explanation:

We need to expand the polynomial $(3c + 2)(c^2-6c-4)$

Multiply the terms:

$(3c + 2)(c^2-6c-4)\\=3c(c^2-6c-4)+2(c^2-6c-4)\\=3c^3-18c^2-12c+2c^2-12c-8\\=3c^3-18c^2+2c^2-12c-12c-8\\=3c^3-16c^2-24c-8$

So, after expanding the polynomial $(3c + 2)(c^2-6c-4)$ we get $3c^3-16c^2-24c-8$

3 0

3 years ago

I really need help with this

ElenaW [278]

Number of boys:
1000/2+20/2=510
Number of girls:
1000/2-20/2=490
510 boys and 490 girls competed at Special Olympics

5 0

3 years ago

What is the result when x^3-2x^2+5x-13x 3 −2x 2 +5x−13 is divided by x-2x−2?

Aleksandr [31]

yo k se wey: rg`weaofjwafgEWF3WRF1QTFG3Q2TGF2

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3 years ago

To find the answers

8_murik_8 [283]

1,876,200 - if it's higher than 5 go up - that means 1,880,000

1,876,200 - means 1,900,000
1,876,200 means 2,000,000

4 0

3 years ago

The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). At which points could the vertex of the right angle in t

Pie

Answer:

(–1, 1) and (4, –2)

Step-by-step explanation:

we know that

The vertex of the right angle of the triangle could be situated at a point with the same x-coordinate of point A and the same y-coordinate of point B or at a point with the same x-coordinate of point B and the same y-coordinate of point A

we have

A(4, 1) and B(–1, –2)

a point with the same x-coordinate of point A and the same y-coordinate of point B is the point (4,-2)

a point with the same x-coordinate of point B and the same y-coordinate of point A is (-1,1)

therefore

(–1, 1) and (4, –2)

3 0

3 years ago

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