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3 years ago

16. The local hiking club went on a 7-day hiking trip to Denali National

Mathematics

1 answer:

Elza [17]3 years ago

5 0

Answer:

The slope of the line is 14 pounds per day

Step-by-step explanation:

We are given that The local hiking club went on a 7-day hiking trip to Denali National Park.

The group started with 98 pounds

We are also given that the decreasing amount of food each day is modeled by a linear function

On Day 1 amount of food = 98 pounds

Since day 7 was the last day

So, On Day 8 amount of food = 0

So, $(x_1,y_1)=(1,98)$

$(x_2,y_2)=(8,0)$

Slope = Constant Rate of change per unit

Slope = $\frac{y_2-y_1}{x_2-x_1}=\frac{0-98}{8-1}$

So, Slope = $\frac{-98}{7}$

Slope = - 14

Negative sign shows decreasing amount of food each day

Hence the slope of the line is 14 pounds per day

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Caitlin says the difference in their ages is 24 years. In two or more complete sentences, explain whether or not Caitlin is corr

Paraphin [41]

~Hello There!~

$\frac{m}{s} =\frac{2}{5}$

Rearrange for s

$s = \frac{5m}{2}$

After 8 years, the new equation would be:

$\frac{m+8}{s+8} =\frac{1}{2}$

Cross multiply

$2m+16 = s+8$

Subtract 8

$2m+8=s$

Substitute old equation

$2m+8 = \frac{5m}{2}$

Solve to get m as 16.

s = 40.

Their current ages are 16 and 40 and the different is 24 years. Therefore, Caitlin is correct.

Hope This Helps You!

Good Luck :)

Have A Great Day ^_^

- Hannah ❤

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3 years ago

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Kaylis [27]

Answer: the 3rd graph cause the other are in the middle well close if that didn't help then i am so sorry if i did plz mark me Brainliest

Step-by-step explanation:

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3 years ago

1. Consider the following hypotheses:

Andrej [43]

Answer:

See deductions below

Step-by-step explanation:

a) p(y)∧q(y) for some y (Existencial instantiation to H1)

b) q(y) for some y (Simplification of a))

c) q(y) → r(y) for all y (Universal instatiation to H2)

d) r(y) for some y (Modus Ponens using b and c)

e) p(y) for some y (Simplification of a)

f) p(y)∧r(y) for some y (Conjunction of d) and e))

g) ∃x (p(x) ∧ r(x)) (Existencial generalization of f)

a) ¬C(x) → ¬A(x) for all x (Universal instatiation of H1)

b) A(x) for some x (Existencial instatiation of H3)

c) ¬(¬C(x)) for some x (Modus Tollens using a and b)

d) C(x) for some x (Double negation of c)

e) A(x) → ∀y B(y) for all x (Universal instantiation of H2)

f) ∀y B(y) (Modus ponens using b and e)

g) B(y) for all y (Universal instantiation of f)

h) B(x)∧C(x) for some x (Conjunction of g and d, selecting y=x on g)

i) ∃x (B(x) ∧ C(x)) (Existencial generalization of h)

3) We will prove that this formula leads to a contradiction.

a) ∀y (P (x, y) ↔ ¬P (y, y)) for some x (Existencial instatiation of hypothesis)

b) P (x, y) ↔ ¬P (y, y) for some x, and for all y (Universal instantiation of a)

c) P (x, x) ↔ ¬P (x, x) (Take y=x in b)

But c) is a contradiction (for example, using truth tables). Hence the formula is not satisfiable.

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3 years ago

Question 6 (Essay Worth 5 points)

Alex17521 [72]

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If i get off my online classes at 11:11 and get back on at 12:26 how much free time do i have?

alexandr1967 [171]

Answer:

1 hr and 45 mins

Step-by-step explanation:

12:26-11:11 or 115, so an hour and 45 mins.

Hope this helps :D

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3 years ago

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