Answer:
If a certain cone with a height of 9 inches has volume V = 3πx2 + 42πx + 147π, what is the cone’s radius r in terms of x?
Step-by-step explanation:
V = 3πx2 + 42πx + 147π
V=3π(x2 + 14x +49)
9.42(x2 + 14x +49)
9.42(x2 + 14x +14) -14 + 49= 0
9.42(x + 7)^2 + 35= 0
9.42(9.42(x + 7)^2 = - 35)9.42
(x + 7)^2 = - 35/9.42)
√(x + 7)^2=√- 35/9.42
x + 7 = - 1.927
x= - 1.927 - 7
x= - 8.927
V = 3π(- 8.927)^2 + 42π(- 8.927) + 147π
V=750.69 - 1177.29 + 461.58
<u>V=34.98</u>
h= 9 inches
V = 13πr2h
34.98 = 13(3.14) (r^2) (h)
34.98 = 40.82 (r^2) 9
34.98 = 367.38 r^2
34.98/ 367.38 = 367.38 r^2/ 367.38
0.095= r^2
Answer:
1 2/14 ; 1 1/7
Step-by-step explanation:
To solve, change the division sign to a multiplication sign and flip the second fraction.
(4/7)/(2/4) = (4/7)(4/2)
Multiply across
(4 * 4)/(7 * 2) = (16)/(14)
Simplify. Change to mixed fraction (& further simplify if needed).
16/14 = 1 2/14
~
Answer: 7
Step-by-step explanation: its correct, trust me
X-y=-10
x=-10-y
7x+7y=-14
7(-10-y)+7y=-14
-70-7y+7y=-14
0y=56
y=0
x=-10-y
x=-10-0
x=-10
I’m not 100% sure if this is right, so I hope someone checks this over :)