Question

What is the molarity of 225 mL of a KNO3 solution containing 34.8 g KNO3? (molar mass = 101.1 g/mol)

Answer 1

Answer:

The answer to your question is the letter B) 1.53 M

Explanation:

Data

Molarity = ?

volume = 225 ml

mass of KNO₃ = 34.8 g

molar mass = 101.1 g/mol

Process

1.- Convert the ml to liters

                  1000 ml ------------------ 1 l

                   225 ml ------------------- x

                   x = (225 x 1) / 1000

                   x = 0.225 l

2.- Convert the mass of KNO₃ to moles

                  101.1 g ---------------------- 1 mol

                   34.8 g --------------------- x

                        x = (34.8 x 1) / 101.1

                        x = 0.344 moles

3.- Calculate the Molarity

Molarity = moles/volume

-Substitution

Molarity = 0.344/ 0.225

-Result

Molarity = 1.53 M

Answer 2

Answer:

B, 1.53 M

Explanation:

Molarity = Moles/ Liter

Moles= 34.8g (1 mol/ 101 g) = .34 mol

Molarity= .34 mol/ .225 L = 1.53M KNO3