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vredina [299]
3 years ago
5

In 2005 the city agency spent $2000 to buy pencils at a cost of $5 a dozen if the agency used 3/4 of these pencils in 2005 and u

se the same number of pencils in 2006 how many more pencils did it have to buy to have enough pencils for all of 2006?
Mathematics
1 answer:
kenny6666 [7]3 years ago
3 0

Answer:the need to buy 3600 pencils.

Step-by-step explanation:

In 2005 the city agency spent $2000 to buy pencils at a cost of $5 a dozen. This means that the number of dozens of pencil that they bought in 2005 is

2000/5 = 400

There are 12 pencils in a dozen. Therefore, total number of pencils that they bought in 2005 is

400 × 12 = 4800 pencils

if the agency used 3/4 of these pencils in 2005, it means that the number of pencils that they used in 2005 is

3/4 × 4800 = 3600

The number of pencils left is

4800 - 3600 = 1200 pencils

If they use the same number of pencils in 2006, then the number of pencils that they have to buy is

4800 - 1200 = 3600 pencils

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Answer:

log2(0.25) = -2

512 = 8^3

Step-by-step explanation:

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Rewrite the following equation in logarithmic form.   0.25 = 2^-2

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Rewrite the following equation in exponential form.  log8 (512) = 3

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3 years ago
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Answer:

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2 years ago
A menu has three meat choices,
wolverine [178]

Answer:

18 ways

Step-by-step explanation:

Number of Meat choices = 3

Number of Vegetable choices = 3

Number of Desserts = 2

Number of ways dinner can be chosen :

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3 * 3 * 2

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4 0
2 years ago
Can someone help me plzzz multiply 46 bye 78
lorasvet [3.4K]
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3 0
3 years ago
Extension question (provide a full explanation of your method(s):
Volgvan

Answer:

Ann has little chance to win if she is presented with 4 counters.

Ann can always win from a pile of 6 counters.

(both are explained below)

Step-by-step explanation:

If Ann  is presented with 4 counters, and

1. if she takes out 3, she will lose since the opponent will  pull out 1 and the last one.

2. if she takes 2 her opponent will take out 1 and she can't pull out the last 1 since her opponents last move was to pull out 1  counter so she will lose.

3. If she takes out 1 and her opponent takes out 3 in the next move she loses.

but if instead of 3 her opponent takes out 2 and in the last move Ann takes out the last 1  then she will win.

So, If Ann is presented with 4 counters she has little chance to win provided in the move just before, her opponent didn't move 1 counter.

Now,

if there is 6 counters to Ann, and

1., if Ben's  previous move was 1 then Ann can win if she takes out 3 or 2.

If she takes out 3 Ben can take out 1 or 2 and in the last move she will take out 2 or 1 (respectively) and winning the game.

If she takes out 2 Ben can  take out 1 or 3 and in the last move Ann wins by pulling out 3 or 1 respectively.

2. if Ben's  previous move was 2 then Ann can win if she takes out 1 or 3.

If she takes out 1 Ben can take out 2 or 3 and in the last move she will take out 3 or 2(respectively) and winning the game.

If she takes out 3 Ben can  take out 1 or 2 and in the last move Ann wins by pulling out 2 or 1 respectively.

2. if Ben's  previous move was 3 then Ann can win if she takes out 1 or 2.

If she takes out 1 Ben can take out 2 or 3 and in the last move she will take out 3 or 2(respectively) and winning the game.

If she takes out 2 Ben can  take out 1 or 3 and in the last move Ann wins by pulling out 3 or 1 respectively.

 

 

7 0
3 years ago
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