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3 years ago

How to do table for given function rule

Mathematics

2 answers:

Rus_ich [418]3 years ago

7 0

Just put your x to equation and you get y.

Ex.

y = -3(-4)+4

y = 12 + 4 = 16

ira [324]3 years ago

6 0

Answer:

these are the numbers that go in the blanks in the y column:

16 4 -8 -20

Step-by-step Explanation:

Since the problem has a key to help us find the answers, it will be much easyer to solve the problem.

We know that the key is

y = -3x + 4

Now lets look at the x column first.

the numbers in the x column will replace the variable in the key.

So for example:

y = -3x + 4 --------> -3 (-8) + 4 = 28

So now we simply do the same process for the other blanks in the y column.

-3 (-4) + 4 = 16

-3 (0) + 4 = 4

-3 (4) + 4 = -8

-3 (8) + 4 = -20

Hope this helped you! Have a blessed day :-)

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3 years ago

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Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

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2 years ago

What are the factors in the expression (a+b)12

BlackZzzverrR [31]

Solution:

1) Distribute
12a+12b

Done!

7 0

3 years ago

How to do table for given function rule​

How to do table for given function rule