Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
 now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
 
        
             
        
        
        
| 42 | The absolute value of forty two
        
                    
             
        
        
        
Sorry, cannot just give you answers without your input.
I'd suggest that you look up online or in your textbook each of the items under "Type of Boundary."  The results you'd get will likely help you fill in the rest of the boxes.
        
             
        
        
        
Answer: 12 days 
Step-by-step explanation:
For us to know the number of days whereby Julie will have both basketball and track practice, we've to find the lowest common multiple of both 6 and 4. This will be:
Multiples of 4 = 4, 8, 12, 16, 24.
Multiples of 6 = 6, 12, 18, 24, 30.
The lowest common multiple is 12. Therefore, she'll have basketball and track practice in 12 days 
 
        
             
        
        
        
Step-by-step explanation:
this creates a right-angled triangle. 
the right angle (90°) being the angle between flag pole and ground. 
the angle ground-wire is 50°.
because we know that the sum of all angles in a triangle is always 180°, we know then that the angle flagpole-wire is
180 - 90 - 50 = 40°
so, we have the situation to know 1 side and all angles. 
to get the other sides we use best the law of sine :
a/sin(A) = b/sin(B) = c/sin(C)
where the sides and related angles are always opposite of each other. 
in our case now we have
24/sin(50) = wire/sin(90) = wire/1 = wire = 31.32977494... ft
so, the rounded answer is that the wire must be
31.3 ft long