Question

The pedigree on the right shows the inheritance pattern for an X-linked recessive disorder.

Answer 1

I'd say your answer would be a 50%-50% chance. So it would be false.

I hoped that helped!

Answer 2

Answer:

100% or 50%

25%

False

Explanation:

From the pedigree, the father of the female circled in pink is affected while the mother is heterozygous for the disorder. If the allele for the disorder is represented by a, then:

$X^aY$   x   $X^AX^a$  = $X^AX^a, X^aX^a, X^AY and X^aY$

It thus means that the female circled in pink is either heterozygous or affected for the disorder with a 50/50 chance in each case. The probability that she is heterozygous or affected for the disorder is therefore 100% or 1.

Now, if the female circled in pink marries an affected male:

$X^aY$   x   $X^AX^a$ = $X^AX^a, X^aX^a, X^AY and X^aY$ (if the female circled in pink is heterozygous for the disorder)

$X^aY$   x   $X^aX^a$ =  $X^aX^a, X^aX^a, X^aY and X^aY$ (if the female circled in pink is affected for the disorder)

The probability that their female child will be affected depends on the genotype of the the female circled in pink. If she is heterozygous, the probability would be 50% while it would be 100% if she is affected by the disorder as shown in the two crosses above.

The chance that the child would be a carrier is the chance that the female circled in pink is be heterozygous and the child being an actual carrier:

1/2 x 1/2 = 1/4 or 25%

The child can never be a standard. The answer is false