The given geometric series as shown in the question is seen to; Be converging with its' sum as 81
<h3>How to identify a converging or diverging series?</h3>
We are given the geometric series;
27 + 18 + 12 + 8 + ...
Now, we see that;
First term; a₀ = 27
Second Term; a₁ = 2(27/3)
Third term; a₂ = 2²(27/3²)
Fourth term; a₃ = 2³(27/3³)
Thus, the formula is;
2ⁿ(27/3ⁿ)
Applying limits at infinity gives;
2^(∞) * (27/3^(∞)) = 0
Since the terms of the series tend to zero, we can affirm that the series converges.
The sum of an infinite converging series is:
S_n = a/(1 - r)
S_n = 27/(1 - (2/3)
S_n = 81
Read more about converging or diverging series at; brainly.com/question/15415793
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Answer:
1056
Step-by-step explanation:
Find the area of each square and add them to find the area of the rectangle
The area of a square = side * side
The areas are:
1*1= 1
4*4 = 16
7*7 = 49
8*8 = 64
9*9 = 81
10*10 = 100
14*14 = 196
15*15 = 225
18*18 = 324
The sum of the areas =
324+225+196+100+81+64+49+16+1
= 1056 units ^2
Answer:
great :) wbu
Step-by-step explanation:
2 1/3 because you ate 3 and have 1/3 left of an orange
#1. B
<span>(z * z^2 + z * 2z + z * 4) – (-2 *z^2 – (-2) 2z – (-2) 4)
Z^3 + 2z^2 + 4z – 2z^2 -4z – 8
Z^3 + 2z^2 – 2z^2 + 4z – 4z – 8
Z^3 - 8
</span>
#2 and #3. D
<span>(x + y)(x + 2)
x^2 + 2x + yx + 2y
</span>
#4. D.
<span>(x - 7)(x + 7)(x- 2)
x^2 + 7x – 7x -49
x^2 + x – 49
x^2 -49
(x^2 – 49 ) (x – 2)
x^3 – 2x^2 – 49x + 98
</span>
#5. C
(y - 4) = 0
y = 4
(x + 3)= 0
x = -3
#6. A and B
