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Andrej [43]
3 years ago
9

Solve the following quadratic inequality 2x^2+3x-5>0

Mathematics
2 answers:
Likurg_2 [28]3 years ago
7 0
The answer is 7x
If is wrong tell me then
madreJ [45]3 years ago
3 0

Answer:

x < -2.5 and x > 1

Step-by-step explanation:

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Is (8,8) a solution to the inequality y &lt; 6x + 5?
NARA [144]

Answer: Yes

Step-by-step explanation: It falls under the shaded area created by y < 6x+5

4 0
3 years ago
Translate into an algebraic expression: If I travel d miles in h hrs downstream on a river with a current of c mph, what would m
xenn [34]

Answer:

The speed is still water is v = \frac{d}{h} - c.

Step-by-step explanation:

Dimentionally speaking, speed is distance divided by time. Since, the person is travelling downstream, absolute speed is equal to the sum of current speed and speed of the person regarding current. Both components are constant. That is:

c + v = \frac{d}{h}

Where:

c - Current speed, measured in miles per hour.

v - Speed of the person regarding current, measured in miles per hour.

d - Distance travelled downstream, measured in miles.

h - Time spent on travelling, measured in hours.

Speed in still water occurs when current speed is zero. Then, such variable is obtained after subtracting current speed on both sides of the expression. Hence:

v = \frac{d}{h} - c

The speed is still water is v = \frac{d}{h} - c.

4 0
3 years ago
The difference between 9/5 and 7/5 is
Agata [3.3K]

Answer:

2/5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A force does 35000J of work along a distance of 10.5m. Find the applied force.
nadezda [96]

Answer: 3333.333 N

Work: To figure it out, you must do 35000J divided by 10.5. After diving, you receive the answer 3333.333N. I hope this helps you!

3 0
3 years ago
Simplify the difference.
mr_godi [17]

\displaystyle\frac{n^2-10n+24}{n^2-13n+42}-\frac{9}{n-7}=\frac{(n-6)(n-4)}{(n-6)(n-7)}-\frac{9}{n-7}\\\\=\frac{n-4}{n-7}-\frac{9}{n-7}=\frac{n-4-9}{n-7}\\\\=\frac{n-13}{n-7}

The last choice is appropriate.

3 0
3 years ago
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