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Andrej [43]
3 years ago
9

Solve the following quadratic inequality 2x^2+3x-5>0

Mathematics
2 answers:
Likurg_2 [28]3 years ago
7 0
The answer is 7x
If is wrong tell me then
madreJ [45]3 years ago
3 0

Answer:

x < -2.5 and x > 1

Step-by-step explanation:

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Find the derivative dy, dx for y equals the quotient of the quantity x cubed minus 5 times x and the quantity x squared minus 1.
Elza [17]
Using the quotient rule  

dy/dx  =  (x^-1) * (3x^2 -5 ) - (x^3 - 5x) * 2x
              ----------------------------------------------
                              (x^2 - 1)^2

You are correct
7 0
3 years ago
A rectangle has a length of x + 7 and a width of x-2. Which equation below describes the perimeter, P, of
valkas [14]

Answer:

            P = 4x  +  10

Step-by-step explanation:

perimeter of a rectangle = 2( width + length )

   P = 2 ( x - 2  +  x + 7 )

   P = 2 ( x + x  +  7 - 2 )

        P = 2 ( 2x +  5 )

            P = 4x  +  10

4 0
2 years ago
Rashawn puts $550 in an account earning 8% simple interest annually. How much will he have in his account after 6 years? i need
Pepsi [2]
It’s funny cause I have a friend named Rashawn
But y intercept would be 550 then multiply 8 by 6to get 48
So your answer should be $598 in 6 years
7 0
3 years ago
Which is the solution set to the inequality (4x-3)(2x-1)&amp;gt=0?
Serjik [45]

(4x - 3)(2x - 1) ≥ 0

First, find the zeros:

4x - 3 = 0         2x - 1 = 0

x = \frac{3}{4}               x = \frac{1}{2}

Next, plot these points and choose test points on the outside and between the zeros:

←-------0------\frac{1}{2}------\frac{5}{8}------\frac{3}{4}------1------→

Lastly, plug in the test points and look for a positive result (since it is greater than 0).

Test Point 0: [4(0) - 3][2(0) - 1]  = ( - )( - ) = +  THIS WORKS!

Test Point \frac{5}{8}: [4(\frac{5}{8}) - 3][2(\frac{5}{8}) - 1]  = ( - )( + ) = -  <em>This does NOT work</em>

Test Point 1: [4(1) - 3][2(1) - 1]  = ( + )( + ) = +  THIS WORKS!

Answer: x ≤ \frac{1}{2}   or   x ≥ \frac{3}{4}

Interval Notation: (-∞, \frac{1}{2}] U [\frac{3}{4}, ∞)

Graph: ←------\frac{1}{2}          \frac{3}{4}--------→

5 0
3 years ago
The number 68 is increased to 73. What is the percentage by which the number was
Murljashka [212]

Answer: 1.1%

Step-by-step explanation:

To get a percentage you want to divide the ending number by the base number

73 / 68 = 1.07

It says to round to the neartest tenth, when rounding if the number is 5 or above you round up, if under 5 your number stays the same

7 is higher than 5 so we round up

1.1%

3 0
2 years ago
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