What we know:
Lot= 21 x 30ft
Perimeter=2l+2w
Want to put 4 corner post and one post every 3 ft
What we need to find:
How many post we need.
Perimeter=2 (21)+2 (30)=42+60=102ft
102/3=34
34 posts are needed.
Answer:
the answer would be C. The mean would increase.
Step-by-step explanation:
Answer:
75.39 in^2 (round to the nearest hundreds)
Step-by-step explanation:
I think that we have to find the lateral area
circumference = 2 x radius x pi = 2 x 4 x pi = 25,13 in^2 (round to the nearest hundreds)
lateral surface = (circumference x slant height)/2 = (25,13 x 6)/2 = 75,39 in^2 (round to the nearest hundreds)
There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.
You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.
-x^6 + 3x^4 + 4x^2
-x^2(x^4 - 3x^2 - 4)
Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.
-x^2(x^4 - 3x^2 - 4)
-x^2(x^2 - 4)(x^2 + 1)
Now we can use the factors of two perfect squares rule to factor the middle parenthesis.
-x^2(x^2 - 4)(x^2 + 1)
-x^2(x - 2)(x + 2)(x^2 + 1)
We would also want to split the term in the front.
-x^2(x - 2)(x + 2)(x^2 + 1)
(x)(-x)(x - 2)(x + 2)(x^2 + 1)
Now we would set each portion equal to 0 and solve.
First root
x = 0 ---> no work needed
Second root
-x = 0 ---> divide by -1
x = 0
Third root
x - 2 = 0
x = 2
Forth root
x + 2 = 0
x = -2
Fifth and Sixth roots
x^2 + 1 = 0
x^2 = -1
x = +/- 
x = +/- i


Remember: PEMDAS - Parentheses, exponents, multiply/divide, add/subtract
Distribute: 9(1+x) = 9+9x
19 - 5x = 9 + 9x
Add 5x to both sides of the equation and subtract 9 from both sides.
19 - 5x + (5x) = 9 + 9x + (5x)
19 - (9) = 9 - (9) + 14x
10 = 14x
Divide both sides by 14 to get the variable on its own.
10/14 = 14x/14
10/14=x
5/7 = x