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Sati [7]
3 years ago
13

Im not sure about this im confused

Mathematics
2 answers:
Maru [420]3 years ago
8 0

Answer:

Step-by-step explanation:

NemiM [27]3 years ago
6 0
The answer is D) the total cost of tiling and fencing the patio
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What's the slope and speed of plane A and B
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The slope and speed of Plane A is 375mph and slope and speed for Plane B is 425 mph... so Plane A travels the fastest
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What kind of angle is shown in the image below
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ACUTE ANGLE.
this is because the angle is less than 90 degree and greater than 0 degree

3 0
3 years ago
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Write an expression in the simplest form that represents the perimeter of the following shape
____ [38]

Perimeter is adding all 4 sides together:

8 + 8 + 9x + 9x

Simplify by coming like terms to get:

18x + 16

The answer is d. 18x + 16

3 0
2 years ago
Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.
gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant  is  mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is  mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)

The partial derivatives of a function are f x and f y.

\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\

&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}

In conclusion,  the area is

A=3 √4 units ^2

Read more about the plane

brainly.com/question/1962726

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5 0
1 year ago
For today only, I am authorizing you to offee a free insurance plan for one year to customer who sign up for our service. The in
dimulka [17.4K]

Answer:

$83.88

Step-by-step explanation:

It will cost 83.88 because there are 12 months in a year, and since it's $6.99 every month we will have to multiply $6.99 by 12 which would give us $83.88

7 0
2 years ago
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