50 students participated in the survey, if you need help with 2, 3, & 4, just comment and ask
Answer:
Step-by-step explanation:
Given that confidence level is 95% and sample mean is within 10 minutes of the population mean. i.e. margin of error = 10
Std deviation of population= 211 minutes
Margin of error = Z critical * std error
Std error = sigma/sq rt n =
Hence we have
\frac{211}{\sqrt{n} }
The minimum sample size is 1710
a) There may not be 1,809 computer users to survey
216/1000
Simplify it by 2
Give me a thanks if it helps!!!
The fraction is 4 1/2. Just convert the decimal into a fraction. 50/100 is the same as 5/10 which is the same as 1/2.