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VikaD [51]
3 years ago
6

$49.50 for 5 1/2 hours

Mathematics
1 answer:
FrozenT [24]3 years ago
7 0

Answer:

5.45

Step-by-step explanation:

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What is the midpoint of the segment shown below (-11,0) (9,-1)
marissa [1.9K]

Answer:

(-1, -1/2)

Step-by-step explanation:

M= (Xa+Xb/2, Ya + Yb/2)


M= -11+9/2  ,  0 + -1/2

M = -2/2, -1/2

M=(-1, -1/2)

6 0
3 years ago
Read 2 more answers
Tyler ate 42 grapes from a bowl. There were 90 grapes in the bowl to begin with. What percent of the grapes did Tyler eat?
Karo-lina-s [1.5K]

Answer:

He ate 42 of the 90 grapes in the bowl

The percentage of grape he ate will be given as this:

42/90 * 100%

=46.67%

Tyler has ate 46.67% of the grapes

4 0
3 years ago
Solve the following system of equations by linear combination: 5x 2y = 14 y = x – 7
natta225 [31]
I would use subsitution
y=x-7
sub x-7 for every x
5x+2(x-7)=14
5x+2x-14=14
add 14 to both sides
7x=28
divide both sides by 7
x=4
sub
y=x-7
y=4-7
y=-3

x=4
y=-3
(4,-3)
4 0
3 years ago
Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar
Mamont248 [21]

Answer:

a

The 95% confidence interval is

   0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

b

  Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

c

 n =  125  \  stores  

Step-by-step explanation:

From the question we are told that

    The sample size is  n =  60  

    The number of stores that had more than 2 items price incorrectly is  k =  52  

   

Generally the sample proportion is mathematically represented as  

             \^ p  =  \frac{ k }{ n }

=>          \^ p  =  \frac{ 52 }{ 60 }

=>          \^ p  =  0.867

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E =  1.96  * \sqrt{\frac{ 0.867  (1- 0.867)}{60} }

=>   E =  0.0859

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.867  - 0.0859  <  p <  0.867  +  0.0859

=>    0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

Considering question b

Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

   

Considering question c

From the question we are told that

    The margin of error is  E = 0.05

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the sample size is mathematically represented as  

    n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=> n=  [\frac{1.645 }}{0.05} ]^2 * 0.867  (1 - 0.867 )

=>   n =  125  \  stores  

4 0
3 years ago
What's the value of given expression :<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B9%7D%20" id="TexFormula1" title=" \
shusha [124]

Answer:

\sqrt{9}  =  \sqrt{3 \times 3}  = 3 \\ thank \: you

4 0
3 years ago
Read 2 more answers
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